本文整理汇总了C++中Bone::display方法的典型用法代码示例。如果您正苦于以下问题：C++ Bone::display方法的具体用法？C++ Bone::display怎么用？C++ Bone::display使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Bone的用法示例。
在下文中一共展示了Bone::display方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: display
bool Board::display() //Displays the board
{
if (!hasSpinner() && rightRow.size() == 0)
return false;
if (!hasSpinner()) //if no spinner is in the board
{
vector<Bone> vecRow = getRow('e');
int numChars = vecRow.size()*4;
numChars = 60 - numChars/2;
int x = numChars;
int y = 27;
for (unsigned int i = 0; i < vecRow.size(); i++)
{
Bone tempBone = vecRow[i];
if (i == 0)
tempBone.swap();
tempBone.display(x,y,'e');
}
}
else //if there is a spinner on the board
{
int tempX = 60;
int tempY = 27;
spinner.display(tempX,tempY,'e');
if (rightRow.size() != 0)
{
int x = 62;
int y = 27;
bool up = false;
bool left = false;
bool lastDouble = false;
for (unsigned int i = 0; i < rightRow.size(); i++) //the following code accounts for the possibility of the bones coming out of the board's limits
{
if (x >= 114 && !up)
{
up = true;
if (lastDouble)
{
y = y - 3;
x = x - 2;
}
else
{
x = x - 2;
y = y - 2;
}
}
if (y <= 8 && !left)
{
left = true;
if (lastDouble)
{
y = y + 2;
x = x - 3;
}
else
{
y = y + 2;
x = x - 2;
}
}
if (up)
if (left)
rightRow[i].display(x,y,'w');
else
rightRow[i].display(x,y,'n');
else
rightRow[i].display(x,y,'e');
if (rightRow[i].isDouble())
lastDouble = true;
else
lastDouble = false;
}
}
if (leftRow.size() != 0)
{
int x = 58;
int y = 27;
bool down = false;
bool right = false;
bool lastDouble = false;
for (unsigned int i = 0; i < leftRow.size(); i++)
{
if (x <= 4 && !down)
{
down = true;
if (lastDouble)
{
x = x + 2;
y = y + 3;
}
else
{
x = x + 2;
y = y + 2;
//.........这里部分代码省略.........