本文整理汇总了C#中FuryOfDracula.GameLogic.GameState.OldestUnrevealedLocationInTrail方法的典型用法代码示例。如果您正苦于以下问题：C# GameState.OldestUnrevealedLocationInTrail方法的具体用法？C# GameState.OldestUnrevealedLocationInTrail怎么用？C# GameState.OldestUnrevealedLocationInTrail使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类FuryOfDracula.GameLogic.GameState的用法示例。
在下文中一共展示了GameState.OldestUnrevealedLocationInTrail方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: ChooseToCancelEventWithDevilishPower
public bool ChooseToCancelEventWithDevilishPower(GameState game, Event eventBeingPlayedNow, Event eventInitiallyPlayed, HunterPlayer hunterPlayingEvent)
{
if (game.Dracula.EventHand.Find(card => card.Event == Event.DevilishPower) != null)
{
int randomChances = 4;
if (eventInitiallyPlayed == Event.DevilishPower && game.HunterAlly != null & game.HunterAlly.Event == Event.SisterAgatha)
{
randomChances = 0;
}
switch (eventInitiallyPlayed)
{
case Event.Evasion: randomChances = (NumberOfPossibleCurrentLocations / 3); break;
case Event.NewspaperReports: if (game.OldestUnrevealedLocationInTrail() == game.Dracula.CurrentLocation)
{
return false;
}
else
{
randomChances = (NumberOfPossibleCurrentLocations / 3);
}
break;
case Event.TimeRunsShort: randomChances = 3; break;
case Event.GoodLuck: randomChances = 2; break;
case Event.HiredScouts: randomChances = (int)((0.75 * (NumberOfPossibleCurrentLocations - 5)) * (0.75 * (NumberOfPossibleCurrentLocations - 5))); break;
}
if (new Random().Next(0, randomChances) == 0)
{
return true;
}
}
return false;
}