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C++ Platform::XtoY方法代码示例

本文整理汇总了C++中Platform::XtoY方法的典型用法代码示例。如果您正苦于以下问题:C++ Platform::XtoY方法的具体用法?C++ Platform::XtoY怎么用?C++ Platform::XtoY使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Platform的用法示例。


在下文中一共展示了Platform::XtoY方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: FollowGround

bool Bipedal::FollowGround(Object & object, World & world, Sint8 velocity){
	if(velocity == 0 || currentplatformid == 0){
		return true;
	}
	object.x += velocity;
	Platform * currentplatform = world.map.platformids[currentplatformid];
	Platform * oldplatform = currentplatform;
	object.y = currentplatform->XtoY(object.x);
	if(object.x > currentplatform->x2){
		velocity = object.x - currentplatform->x2;
		object.x = currentplatform->x2;
		currentplatform = currentplatform->adjacentr;
	}else
	if(object.x < currentplatform->x1){
		velocity = -(Sint8)(currentplatform->x1 - object.x);
		object.x = currentplatform->x1;
		currentplatform = currentplatform->adjacentl;
	}else{
		return true;
	}
	if(currentplatform){
		currentplatformid = currentplatform->id;
		return FollowGround(object, world, velocity);
	}else{
		Platform * collided = world.map.TestAABB(object.x, object.y - height, object.x, object.y, Platform::RECTANGLE | Platform::STAIRSUP | Platform::STAIRSDOWN, oldplatform);
		if(collided){
			return true;
		}
		return false;
	}
	return true;
}
开发者ID:Phobia0ptik,项目名称:zSILENCER,代码行数:32,代码来源:bipedal.cpp

示例2: FindCurrentPlatform

bool Bipedal::FindCurrentPlatform(Object & object, World & world){
	if(currentplatformid){
		return true;
	}
	int xv2 = 0;
	int yv2 = 1;
	Platform * platform = world.map.TestIncr(object.x, object.y - height, object.x, object.y, &xv2, &yv2, Platform::RECTANGLE | Platform::STAIRSUP | Platform::STAIRSDOWN);
	if(platform){
		currentplatformid = platform->id;
		object.y = platform->XtoY(object.x);
		return true;
	}
	return false;
}
开发者ID:Phobia0ptik,项目名称:zSILENCER,代码行数:14,代码来源:bipedal.cpp


注:本文中的Platform::XtoY方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。