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C# IRenderContext.LocateView方法代码示例

本文整理汇总了C#中IRenderContext.LocateView方法的典型用法代码示例。如果您正苦于以下问题:C# IRenderContext.LocateView方法的具体用法?C# IRenderContext.LocateView怎么用?C# IRenderContext.LocateView使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在IRenderContext的用法示例。


在下文中一共展示了IRenderContext.LocateView方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: RenderView

        /// <summary>
        /// Renders the view.
        /// </summary>
        /// <param name="viewLocationResult">A <see cref="ViewLocationResult"/> instance, containing information on how to get the view template.</param>
        /// <param name="model">The model that should be passed into the view</param>
        /// <param name="renderContext">The render context.</param>
        /// <param name="isPartial">Used by HtmlHelpers to declare a view as partial</param>
        /// <returns>A response.</returns>
        public Response RenderView(ViewLocationResult viewLocationResult, dynamic model, IRenderContext renderContext, bool isPartial)
        {
            Assembly referencingAssembly = null;

            if (model != null)
            {
                var underlyingSystemType = model.GetType().UnderlyingSystemType;
                if (underlyingSystemType != null)
                {
                    referencingAssembly = Assembly.GetAssembly(underlyingSystemType);
                }
            }

            var response = new HtmlResponse();

            response.Contents = stream =>
            {
                var writer =
                    new StreamWriter(stream);

                var view = this.GetViewInstance(viewLocationResult, renderContext, referencingAssembly, model);

                view.ExecuteView(null, null);

                var body = view.Body;
                var sectionContents = view.SectionContents;

                var layout = view.HasLayout ? view.Layout : GetViewStartLayout(model, renderContext, referencingAssembly, isPartial);

                var root = string.IsNullOrWhiteSpace(layout);

                while (!root)
                {
                    view = this.GetViewInstance(renderContext.LocateView(layout, model), renderContext, referencingAssembly, model);

                    view.ExecuteView(body, sectionContents);

                    body = view.Body;
                    sectionContents = view.SectionContents;

                    layout = view.HasLayout ? view.Layout : GetViewStartLayout(model, renderContext, referencingAssembly, isPartial);

                    root = !view.HasLayout;
                }

                writer.Write(body);
                writer.Flush();
            };

            return response;
        }
开发者ID:JulianRooze,项目名称:Nancy,代码行数:59,代码来源:RazorViewEngine.cs

示例2: GetViewStartLayout

        private string GetViewStartLayout(dynamic model, IRenderContext renderContext, Assembly referencingAssembly, bool isPartial)
        {
            if (isPartial)
            {
                return string.Empty;
            }

            var view = renderContext.LocateView("_ViewStart", model);

            if (view == null)
            {
                return string.Empty;
            }

            if (!this.Extensions.Any(x => x.Equals(view.Extension, StringComparison.OrdinalIgnoreCase)))
            {
                return string.Empty;
            }

            var viewInstance = GetViewInstance(view, renderContext, referencingAssembly, model);

            viewInstance.ExecuteView(null, null);

            return viewInstance.Layout ?? string.Empty;
        }
开发者ID:JulianRooze,项目名称:Nancy,代码行数:25,代码来源:RazorViewEngine.cs

示例3: RenderView

        /// <summary>
        /// Renders the view.
        /// </summary>
        /// <param name="viewLocationResult">A <see cref="ViewLocationResult"/> instance, containing information on how to get the view template.</param>
        /// <param name="model">The model that should be passed into the view</param>
        /// <param name="renderContext">The render context.</param>
        /// <param name="isPartial">Used by HtmlHelpers to declare a view as partial</param>
        /// <returns>A response.</returns>
        public Response RenderView(ViewLocationResult viewLocationResult, dynamic model, IRenderContext renderContext, bool isPartial)
        {
            Assembly referencingAssembly = null;

            var response = new HtmlResponse();

            response.Contents = stream =>
            {
                var writer =
                    new StreamWriter(stream);

                var view = this.GetViewInstance(viewLocationResult, renderContext, model);

                view.ExecuteView(null, null);

                var body = view.Body;
                var sectionContents = view.SectionContents;

                var layout = view.HasLayout ? view.Layout : GetViewStartLayout(model, renderContext, referencingAssembly, isPartial);

                var root = string.IsNullOrWhiteSpace(layout);

                while (!root)
                {
                    var viewLocation =
                        renderContext.LocateView(layout, model);

                    if (viewLocation == null)
                    {
                        throw new InvalidOperationException("Unable to locate layout: " + layout);
                    }

                    view = this.GetViewInstance(viewLocation, renderContext, model);

                    view.ExecuteView(body, sectionContents);

                    body = view.Body;
                    sectionContents = view.SectionContents;

                    layout = view.HasLayout ? view.Layout : GetViewStartLayout(model, renderContext, referencingAssembly, isPartial);

                    root = !view.HasLayout;
                }

                writer.Write(body);
                writer.Flush();
            };

            return response;
        }
开发者ID:VPashkov,项目名称:Nancy,代码行数:58,代码来源:RazorViewEngine.cs


注:本文中的IRenderContext.LocateView方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。