本文整理汇总了C#中BigInteger.equals方法的典型用法代码示例。如果您正苦于以下问题：C# BigInteger.equals方法的具体用法？C# BigInteger.equals怎么用？C# BigInteger.equals使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类BigInteger的用法示例。
在下文中一共展示了BigInteger.equals方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: and
/** @see BigInteger#and(BigInteger) */
internal static BigInteger and(BigInteger val, BigInteger that)
{
if (that.sign == 0 || val.sign == 0) {
return BigInteger.ZERO;
}
if (that.equals(BigInteger.MINUS_ONE)){
return val;
}
if (val.equals(BigInteger.MINUS_ONE)) {
return that;
}
if (val.sign > 0) {
if (that.sign > 0) {
return andPositive(val, that);
} else {
return andDiffSigns(val, that);
}
} else {
if (that.sign > 0) {
return andDiffSigns(that, val);
} else if (val.numberLength > that.numberLength) {
return andNegative(val, that);
} else {
return andNegative(that, val);
}
}
}示例2: xor
/** @see BigInteger#xor(BigInteger) */
internal static BigInteger xor(BigInteger val, BigInteger that)
{
if (that.sign == 0) {
return val;
}
if (val.sign == 0) {
return that;
}
if (that.equals(BigInteger.MINUS_ONE)) {
return val.not();
}
if (val.equals(BigInteger.MINUS_ONE)) {
return that.not();
}
if (val.sign > 0) {
if (that.sign > 0) {
if (val.numberLength > that.numberLength) {
return xorPositive(val, that);
} else {
return xorPositive(that, val);
}
} else {
return xorDiffSigns(val, that);
}
} else {
if (that.sign > 0) {
return xorDiffSigns(that, val);
} else if (that.getFirstNonzeroDigit() > val.getFirstNonzeroDigit()) {
return xorNegative(that, val);
} else {
return xorNegative(val, that);
}
}
}示例3: not
/** @see BigInteger#not() */
internal static BigInteger not(BigInteger val)
{
if (val.sign == 0) {
return BigInteger.MINUS_ONE;
}
if (val.equals(BigInteger.MINUS_ONE)) {
return BigInteger.ZERO;
}
int []resDigits = new int[val.numberLength + 1];
int i;
if (val.sign > 0) {
// ~val = -val + 1
if (val.digits[val.numberLength - 1] != -1) {
for (i = 0; val.digits[i] == -1; i++) {
;
}
} else {
for (i = 0; (i < val.numberLength) && (val.digits[i] == -1); i++) {
;
}
if (i == val.numberLength) {
resDigits[i] = 1;
return new BigInteger(-val.sign, i + 1, resDigits);
}
}
// Here a carry 1 was generated
} else {// (val.sign < 0)
// ~val = -val - 1
for (i = 0; val.digits[i] == 0; i++) {
resDigits[i] = -1;
}
// Here a borrow -1 was generated
}
// Now, the carry/borrow can be absorbed
resDigits[i] = val.digits[i] + val.sign;
// Copying the remaining unchanged digit
for (i++; i < val.numberLength; i++) {
resDigits[i] = val.digits[i];
}
return new BigInteger(-val.sign, i, resDigits);
}示例4: andNot
/** @see BigInteger#andNot(BigInteger) */
internal static BigInteger andNot(BigInteger val, BigInteger that)
{
if (that.sign == 0 ) {
return val;
}
if (val.sign == 0) {
return BigInteger.ZERO;
}
if (val.equals(BigInteger.MINUS_ONE)) {
return that.not();
}
if (that.equals(BigInteger.MINUS_ONE)){
return BigInteger.ZERO;
}
//if val == that, return 0
if (val.sign > 0) {
if (that.sign > 0) {
return andNotPositive(val, that);
} else {
return andNotPositiveNegative(val, that);
}
} else {
if (that.sign > 0) {
return andNotNegativePositive(val, that);
} else {
return andNotNegative(val, that);
}
}
}