本文整理汇总了C++中APInt::countTrailingZeros方法的典型用法代码示例。如果您正苦于以下问题:C++ APInt::countTrailingZeros方法的具体用法?C++ APInt::countTrailingZeros怎么用?C++ APInt::countTrailingZeros使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类APInt
的用法示例。
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示例1: determineLiveOperandBits
void BDCE::determineLiveOperandBits(const Instruction *UserI,
const Instruction *I, unsigned OperandNo,
const APInt &AOut, APInt &AB,
APInt &KnownZero, APInt &KnownOne,
APInt &KnownZero2, APInt &KnownOne2) {
unsigned BitWidth = AB.getBitWidth();
// We're called once per operand, but for some instructions, we need to
// compute known bits of both operands in order to determine the live bits of
// either (when both operands are instructions themselves). We don't,
// however, want to do this twice, so we cache the result in APInts that live
// in the caller. For the two-relevant-operands case, both operand values are
// provided here.
auto ComputeKnownBits =
[&](unsigned BitWidth, const Value *V1, const Value *V2) {
const DataLayout &DL = I->getModule()->getDataLayout();
KnownZero = APInt(BitWidth, 0);
KnownOne = APInt(BitWidth, 0);
computeKnownBits(const_cast<Value *>(V1), KnownZero, KnownOne, DL, 0,
AC, UserI, DT);
if (V2) {
KnownZero2 = APInt(BitWidth, 0);
KnownOne2 = APInt(BitWidth, 0);
computeKnownBits(const_cast<Value *>(V2), KnownZero2, KnownOne2, DL,
0, AC, UserI, DT);
}
};
switch (UserI->getOpcode()) {
default: break;
case Instruction::Call:
case Instruction::Invoke:
if (const IntrinsicInst *II = dyn_cast<IntrinsicInst>(UserI))
switch (II->getIntrinsicID()) {
default: break;
case Intrinsic::bswap:
// The alive bits of the input are the swapped alive bits of
// the output.
AB = AOut.byteSwap();
break;
case Intrinsic::ctlz:
if (OperandNo == 0) {
// We need some output bits, so we need all bits of the
// input to the left of, and including, the leftmost bit
// known to be one.
ComputeKnownBits(BitWidth, I, nullptr);
AB = APInt::getHighBitsSet(BitWidth,
std::min(BitWidth, KnownOne.countLeadingZeros()+1));
}
break;
case Intrinsic::cttz:
if (OperandNo == 0) {
// We need some output bits, so we need all bits of the
// input to the right of, and including, the rightmost bit
// known to be one.
ComputeKnownBits(BitWidth, I, nullptr);
AB = APInt::getLowBitsSet(BitWidth,
std::min(BitWidth, KnownOne.countTrailingZeros()+1));
}
break;
}
break;
case Instruction::Add:
case Instruction::Sub:
// Find the highest live output bit. We don't need any more input
// bits than that (adds, and thus subtracts, ripple only to the
// left).
AB = APInt::getLowBitsSet(BitWidth, AOut.getActiveBits());
break;
case Instruction::Shl:
if (OperandNo == 0)
if (ConstantInt *CI =
dyn_cast<ConstantInt>(UserI->getOperand(1))) {
uint64_t ShiftAmt = CI->getLimitedValue(BitWidth-1);
AB = AOut.lshr(ShiftAmt);
// If the shift is nuw/nsw, then the high bits are not dead
// (because we've promised that they *must* be zero).
const ShlOperator *S = cast<ShlOperator>(UserI);
if (S->hasNoSignedWrap())
AB |= APInt::getHighBitsSet(BitWidth, ShiftAmt+1);
else if (S->hasNoUnsignedWrap())
AB |= APInt::getHighBitsSet(BitWidth, ShiftAmt);
}
break;
case Instruction::LShr:
if (OperandNo == 0)
if (ConstantInt *CI =
dyn_cast<ConstantInt>(UserI->getOperand(1))) {
uint64_t ShiftAmt = CI->getLimitedValue(BitWidth-1);
AB = AOut.shl(ShiftAmt);
// If the shift is exact, then the low bits are not dead
// (they must be zero).
if (cast<LShrOperator>(UserI)->isExact())
AB |= APInt::getLowBitsSet(BitWidth, ShiftAmt);
}
break;
case Instruction::AShr:
//.........这里部分代码省略.........