当前位置: 首页>>代码示例>>C#>>正文


C# Position.attackers_to方法代码示例

本文整理汇总了C#中Portfish.Position.attackers_to方法的典型用法代码示例。如果您正苦于以下问题:C# Position.attackers_to方法的具体用法?C# Position.attackers_to怎么用?C# Position.attackers_to使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Portfish.Position的用法示例。


在下文中一共展示了Position.attackers_to方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: generate_castle

        private static void generate_castle(CastlingSide Side, bool OnlyChecks, Position pos, MoveStack[] ms, ref int mpos, Color us)
        {
            if (pos.castle_impeded(us, Side) || (pos.can_castle_CR(Utils.make_castle_right(us, Side))==0) )
                return;

            // After castling, the rook and king final positions are the same in Chess960
            // as they would be in standard chess.
            Square kfrom = pos.king_square(us);
            Square rfrom = pos.castle_rook_square(us, Side);
            Square kto = Utils.relative_square(us, Side == CastlingSideC.KING_SIDE ? SquareC.SQ_G1 : SquareC.SQ_C1);

            Bitboard enemies = pos.pieces_C(us ^ 1);

            Debug.Assert(!pos.in_check());

            for (Square s = Math.Min(kfrom, kto), e = Math.Max(kfrom, kto); s <= e; s++)
                if (s != kfrom // We are not in check
                    && ((pos.attackers_to(s) & enemies) != 0))
                    return;

            // Because we generate only legal castling moves we need to verify that
            // when moving the castling rook we do not discover some hidden checker.
            // For instance an enemy queen in SQ_A1 when castling rook is in SQ_B1.
            if (pos.chess960
                && ((pos.attackers_to(kto, Utils.xor_bit(pos.occupied_squares, rfrom)) & enemies) != 0))
                return;

            Move m = Utils.make_castle(kfrom, rfrom);

            if (OnlyChecks)
            {
                CheckInfo ci = CheckInfoBroker.GetObject();
                ci.CreateCheckInfo(pos);
                bool givesCheck = pos.move_gives_check(m, ci);
                CheckInfoBroker.Free();
                if (!givesCheck) return;
            }

            ms[mpos++].move = m;
        }
开发者ID:CVChrisWilson,项目名称:Portfish,代码行数:40,代码来源:Movegen.cs

示例2: move_to_san

        /// move_to_san() takes a position and a move as input, where it is assumed
        /// that the move is a legal move for the position. The return value is
        /// a string containing the move in short algebraic notation.
        internal static string move_to_san(Position pos, Move m)
        {
            if (m == MoveC.MOVE_NONE)
                return "(none)";

            if (m == MoveC.MOVE_NULL)
                return "(null)";

            Debug.Assert(is_ok_M(m));

            Bitboard attackers;
            bool ambiguousMove, ambiguousFile, ambiguousRank;
            Square sq, from = from_sq(m);
            Square to = to_sq(m);
            PieceType pt = type_of(pos.piece_moved(m));

            StringBuilder san = new StringBuilder();

            if (is_castle(m))
                san.Append((to_sq(m) < from_sq(m) ? "O-O-O" : "O-O"));
            else
            {
                if (pt != PieceTypeC.PAWN)
                {
                    san.Append(piece_type_to_char(pt).ToString());

                    // Disambiguation if we have more then one piece with destination 'to'
                    // note that for pawns is not needed because starting file is explicit.
                    attackers = pos.attackers_to(to) & pos.pieces_PTC(pt, pos.sideToMove);
                    xor_bit(ref attackers, from);
                    ambiguousMove = ambiguousFile = ambiguousRank = false;

                    while (attackers != 0)
                    {
                        sq = pop_1st_bit(ref attackers);

                        // Pinned pieces are not included in the possible sub-set
                        if (!pos.pl_move_is_legal(make_move(sq, to), pos.pinned_pieces()))
                            continue;

                        if (file_of(sq) == file_of(from))
                            ambiguousFile = true;

                        if (rank_of(sq) == rank_of(from))
                            ambiguousRank = true;

                        ambiguousMove = true;
                    }

                    if (ambiguousMove)
                    {
                        if (!ambiguousFile)
                            san.Append(file_to_char(file_of(from)));
                        else if (!ambiguousRank)
                            san.Append(rank_to_char(rank_of(from)));
                        else
                            san.Append(square_to_string(from));
                    }
                }

                if (pos.is_capture(m))
                {
                    if (pt == PieceTypeC.PAWN)
                        san.Append(file_to_char(file_of(from)));

                    san.Append('x');
                }

                san.Append(square_to_string(to));

                if (is_promotion(m))
                {
                    san.Append('=');
                    san.Append(piece_type_to_char(promotion_type(m)));
                }
            }

            CheckInfo ci = CheckInfoBroker.GetObject();
            ci.CreateCheckInfo(pos);
            if (pos.move_gives_check(m, ci))
            {
                StateInfo st = new StateInfo();
                pos.do_move(m, st);
                MList mlist = MListBroker.GetObject(); mlist.pos = 0;
                Movegen.generate_legal(pos, mlist.moves, ref mlist.pos);
                san.Append(mlist.pos > 0 ? "+" : "#");
                MListBroker.Free();
                pos.undo_move(m);
            }
            CheckInfoBroker.Free();

            return san.ToString();
        }
开发者ID:stevemulligan,项目名称:Portfish,代码行数:96,代码来源:Utils.cs

示例3: generate_castle

        private static void generate_castle(
            int Side,
            bool Checks,
            Position pos,
            MoveStack[] ms,
            ref int mpos,
            int us)
        {
            if (pos.castle_impeded(us, Side) || (pos.can_castle_CR(Utils.make_castle_right(us, Side)) == 0))
            {
                return;
            }

            // After castling, the rook and king final positions are the same in Chess960
            // as they would be in standard chess.
            var kfrom = pos.king_square(us);
            var rfrom = pos.castle_rook_square(us, Side);
            var kto = Utils.relative_square(us, Side == CastlingSideC.KING_SIDE ? SquareC.SQ_G1 : SquareC.SQ_C1);

            var enemies = pos.pieces_C(us ^ 1);

            Debug.Assert(!pos.in_check());

            int K = pos.chess960 ? kto > kfrom ? -1 : 1 : Side == CastlingSideC.KING_SIDE ? -1 : 1;
            
            for (Square s = kto; s != kfrom; s += (Square)K)
            {
                if ((pos.attackers_to(s) & enemies) != 0)
                {
                    return;
                }
            }

            // Because we generate only legal castling moves we need to verify that
            // when moving the castling rook we do not discover some hidden checker.
            // For instance an enemy queen in SQ_A1 when castling rook is in SQ_B1.
            if (pos.chess960 && ((pos.attackers_to(kto, Utils.xor_bit(pos.occupied_squares, rfrom)) & enemies) != 0))
            {
                return;
            }

            var m = Utils.make(kfrom, rfrom, MoveTypeC.CASTLING);

            if (Checks)
            {
                var ci = CheckInfoBroker.GetObject();
                ci.CreateCheckInfo(pos);
                var givesCheck = pos.move_gives_check(m, ci);
                CheckInfoBroker.Free();
                if (!givesCheck)
                {
                    return;
                }
            }

            ms[mpos++].move = m;
        }
开发者ID:torfranz,项目名称:Portfish,代码行数:57,代码来源:Movegen.cs


注:本文中的Portfish.Position.attackers_to方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。