本文整理汇总了C++中Triangle::PointCCW方法的典型用法代码示例。如果您正苦于以下问题:C++ Triangle::PointCCW方法的具体用法?C++ Triangle::PointCCW怎么用?C++ Triangle::PointCCW使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Triangle
的用法示例。
在下文中一共展示了Triangle::PointCCW方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: FlipScanEdgeEvent
void Sweep::FlipScanEdgeEvent(SweepContext& tcx, Point& ep, Point& eq, Triangle& flip_triangle,
Triangle& t, Point& p)
{
Triangle& ot = t.NeighborAcross(p);
Point& op = *ot.OppositePoint(t, p);
if (&t.NeighborAcross(p) == NULL) {
// If we want to integrate the fillEdgeEvent do it here
// With current implementation we should never get here
//throw new RuntimeException( "[BUG:FIXME] FLIP failed due to missing triangle");
assert(0);
}
if (InScanArea(eq, *flip_triangle.PointCCW(eq), *flip_triangle.PointCW(eq), op)) {
// flip with new edge op->eq
FlipEdgeEvent(tcx, eq, op, &ot, op);
// TODO: Actually I just figured out that it should be possible to
// improve this by getting the next ot and op before the the above
// flip and continue the flipScanEdgeEvent here
// set new ot and op here and loop back to inScanArea test
// also need to set a new flip_triangle first
// Turns out at first glance that this is somewhat complicated
// so it will have to wait.
} else{
Point& newP = NextFlipPoint(ep, eq, ot, op);
FlipScanEdgeEvent(tcx, ep, eq, flip_triangle, ot, newP);
}
}
示例2: Legalize
bool Sweep::Legalize(SweepContext& tcx, Triangle& t)
{
// To legalize a triangle we start by finding if any of the three edges
// violate the Delaunay condition
for (int i = 0; i < 3; i++) {
if (t.delaunay_edge[i])
continue;
Triangle* ot = t.GetNeighbor(i);
if (ot) {
Point* p = t.GetPoint(i);
Point* op = ot->OppositePoint(t, *p);
int oi = ot->Index(op);
// If this is a Constrained Edge or a Delaunay Edge(only during recursive legalization)
// then we should not try to legalize
if (ot->constrained_edge[oi] || ot->delaunay_edge[oi]) {
t.constrained_edge[i] = ot->constrained_edge[oi];
continue;
}
bool inside = Incircle(*p, *t.PointCCW(*p), *t.PointCW(*p), *op);
if (inside) {
// Lets mark this shared edge as Delaunay
t.delaunay_edge[i] = true;
ot->delaunay_edge[oi] = true;
// Lets rotate shared edge one vertex CW to legalize it
RotateTrianglePair(t, *p, *ot, *op);
// We now got one valid Delaunay Edge shared by two triangles
// This gives us 4 new edges to check for Delaunay
// Make sure that triangle to node mapping is done only one time for a specific triangle
bool not_legalized = !Legalize(tcx, t);
if (not_legalized) {
tcx.MapTriangleToNodes(t);
}
not_legalized = !Legalize(tcx, *ot);
if (not_legalized)
tcx.MapTriangleToNodes(*ot);
// Reset the Delaunay edges, since they only are valid Delaunay edges
// until we add a new triangle or point.
// XXX: need to think about this. Can these edges be tried after we
// return to previous recursive level?
t.delaunay_edge[i] = false;
ot->delaunay_edge[oi] = false;
// If triangle have been legalized no need to check the other edges since
// the recursive legalization will handles those so we can end here.
return true;
}
}
}
return false;
}