本文整理汇总了C++中TType::isScalar方法的典型用法代码示例。如果您正苦于以下问题:C++ TType::isScalar方法的具体用法?C++ TType::isScalar怎么用?C++ TType::isScalar使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类TType
的用法示例。
在下文中一共展示了TType::isScalar方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: computeTypeXfbSize
// Recursively figure out how many bytes of xfb buffer are used by the given type.
// Return the size of type, in bytes.
// Sets containsDouble to true if the type contains a double.
// N.B. Caller must set containsDouble to false before calling.
unsigned int TIntermediate::computeTypeXfbSize(const TType& type, bool& containsDouble) const
{
// "...if applied to an aggregate containing a double, the offset must also be a multiple of 8,
// and the space taken in the buffer will be a multiple of 8.
// ...within the qualified entity, subsequent components are each
// assigned, in order, to the next available offset aligned to a multiple of
// that component's size. Aggregate types are flattened down to the component
// level to get this sequence of components."
if (type.isArray()) {
// TODO: perf: this can be flattened by using getCumulativeArraySize(), and a deref that discards all arrayness
assert(type.isExplicitlySizedArray());
TType elementType(type, 0);
return type.getOuterArraySize() * computeTypeXfbSize(elementType, containsDouble);
}
if (type.isStruct()) {
unsigned int size = 0;
bool structContainsDouble = false;
for (int member = 0; member < (int)type.getStruct()->size(); ++member) {
TType memberType(type, member);
// "... if applied to
// an aggregate containing a double, the offset must also be a multiple of 8,
// and the space taken in the buffer will be a multiple of 8."
bool memberContainsDouble = false;
int memberSize = computeTypeXfbSize(memberType, memberContainsDouble);
if (memberContainsDouble) {
structContainsDouble = true;
RoundToPow2(size, 8);
}
size += memberSize;
}
if (structContainsDouble) {
containsDouble = true;
RoundToPow2(size, 8);
}
return size;
}
int numComponents;
if (type.isScalar())
numComponents = 1;
else if (type.isVector())
numComponents = type.getVectorSize();
else if (type.isMatrix())
numComponents = type.getMatrixCols() * type.getMatrixRows();
else {
assert(0);
numComponents = 1;
}
if (type.getBasicType() == EbtDouble) {
containsDouble = true;
return 8 * numComponents;
} else
return 4 * numComponents;
}
示例2: computeTypeLocationSize
// Recursively figure out how many locations are used up by an input or output type.
// Return the size of type, as measured by "locations".
int TIntermediate::computeTypeLocationSize(const TType& type) const
{
// "If the declared input is an array of size n and each element takes m locations, it will be assigned m * n
// consecutive locations..."
if (type.isArray()) {
// TODO: perf: this can be flattened by using getCumulativeArraySize(), and a deref that discards all arrayness
TType elementType(type, 0);
if (type.isImplicitlySizedArray()) {
// TODO: are there valid cases of having an implicitly-sized array with a location? If so, running this code too early.
return computeTypeLocationSize(elementType);
} else
return type.getOuterArraySize() * computeTypeLocationSize(elementType);
}
// "The locations consumed by block and structure members are determined by applying the rules above
// recursively..."
if (type.isStruct()) {
int size = 0;
for (int member = 0; member < (int)type.getStruct()->size(); ++member) {
TType memberType(type, member);
size += computeTypeLocationSize(memberType);
}
return size;
}
// ES: "If a shader input is any scalar or vector type, it will consume a single location."
// Desktop: "If a vertex shader input is any scalar or vector type, it will consume a single location. If a non-vertex
// shader input is a scalar or vector type other than dvec3 or dvec4, it will consume a single location, while
// types dvec3 or dvec4 will consume two consecutive locations. Inputs of type double and dvec2 will
// consume only a single location, in all stages."
if (type.isScalar())
return 1;
if (type.isVector()) {
if (language == EShLangVertex && type.getQualifier().isPipeInput())
return 1;
if (type.getBasicType() == EbtDouble && type.getVectorSize() > 2)
return 2;
else
return 1;
}
// "If the declared input is an n x m single- or double-precision matrix, ...
// The number of locations assigned for each matrix will be the same as
// for an n-element array of m-component vectors..."
if (type.isMatrix()) {
TType columnType(type, 0);
return type.getMatrixCols() * computeTypeLocationSize(columnType);
}
assert(0);
return 1;
}
示例3: GLVariableType
GLenum GLVariableType(const TType &type)
{
if (type.getBasicType() == EbtFloat)
{
if (type.isScalar())
{
return GL_FLOAT;
}
else if (type.isVector())
{
switch (type.getNominalSize())
{
case 2: return GL_FLOAT_VEC2;
case 3: return GL_FLOAT_VEC3;
case 4: return GL_FLOAT_VEC4;
default: UNREACHABLE();
}
}
else if (type.isMatrix())
{
switch (type.getCols())
{
case 2:
switch (type.getRows())
{
case 2: return GL_FLOAT_MAT2;
case 3: return GL_FLOAT_MAT2x3;
case 4: return GL_FLOAT_MAT2x4;
default: UNREACHABLE();
}
case 3:
switch (type.getRows())
{
case 2: return GL_FLOAT_MAT3x2;
case 3: return GL_FLOAT_MAT3;
case 4: return GL_FLOAT_MAT3x4;
default: UNREACHABLE();
}
case 4:
switch (type.getRows())
{
case 2: return GL_FLOAT_MAT4x2;
case 3: return GL_FLOAT_MAT4x3;
case 4: return GL_FLOAT_MAT4;
default: UNREACHABLE();
}
default: UNREACHABLE();
}
}
else UNREACHABLE();
}
else if (type.getBasicType() == EbtInt)
{
if (type.isScalar())
{
return GL_INT;
}
else if (type.isVector())
{
switch (type.getNominalSize())
{
case 2: return GL_INT_VEC2;
case 3: return GL_INT_VEC3;
case 4: return GL_INT_VEC4;
default: UNREACHABLE();
}
}
else UNREACHABLE();
}
else if (type.getBasicType() == EbtUInt)
{
if (type.isScalar())
{
return GL_UNSIGNED_INT;
}
else if (type.isVector())
{
switch (type.getNominalSize())
{
case 2: return GL_UNSIGNED_INT_VEC2;
case 3: return GL_UNSIGNED_INT_VEC3;
case 4: return GL_UNSIGNED_INT_VEC4;
default: UNREACHABLE();
}
}
else UNREACHABLE();
}
else if (type.getBasicType() == EbtBool)
{
if (type.isScalar())
{
return GL_BOOL;
}
else if (type.isVector())
{
switch (type.getNominalSize())
{
//.........这里部分代码省略.........
示例4: getBaseAlignment
//.........这里部分代码省略.........
//
// 8. If the member is an array of S row-major matrices with C columns and R
// rows, the matrix is stored identically to a row of S R row vectors with C
// components each, according to rule (4).
//
// 9. If the member is a structure, the base alignment of the structure is N , where
// N is the largest base alignment value of any of its members, and rounded
// up to the base alignment of a vec4. The individual members of this substructure
// are then assigned offsets by applying this set of rules recursively,
// where the base offset of the first member of the sub-structure is equal to the
// aligned offset of the structure. The structure may have padding at the end;
// the base offset of the member following the sub-structure is rounded up to
// the next multiple of the base alignment of the structure.
//
// 10. If the member is an array of S structures, the S elements of the array are laid
// out in order, according to rule (9).
//
// Assuming, for rule 10: The stride is the same as the size of an element.
stride = 0;
int dummyStride;
// rules 4, 6, 8, and 10
if (type.isArray()) {
// TODO: perf: this might be flattened by using getCumulativeArraySize(), and a deref that discards all arrayness
TType derefType(type, 0);
alignment = getBaseAlignment(derefType, size, dummyStride, std140, rowMajor);
if (std140)
alignment = std::max(baseAlignmentVec4Std140, alignment);
RoundToPow2(size, alignment);
stride = size; // uses full matrix size for stride of an array of matrices (not quite what rule 6/8, but what's expected)
// uses the assumption for rule 10 in the comment above
size = stride * type.getOuterArraySize();
return alignment;
}
// rule 9
if (type.getBasicType() == EbtStruct) {
const TTypeList& memberList = *type.getStruct();
size = 0;
int maxAlignment = std140 ? baseAlignmentVec4Std140 : 0;
for (size_t m = 0; m < memberList.size(); ++m) {
int memberSize;
// modify just the children's view of matrix layout, if there is one for this member
TLayoutMatrix subMatrixLayout = memberList[m].type->getQualifier().layoutMatrix;
int memberAlignment = getBaseAlignment(*memberList[m].type, memberSize, dummyStride, std140,
(subMatrixLayout != ElmNone) ? (subMatrixLayout == ElmRowMajor) : rowMajor);
maxAlignment = std::max(maxAlignment, memberAlignment);
RoundToPow2(size, memberAlignment);
size += memberSize;
}
// The structure may have padding at the end; the base offset of
// the member following the sub-structure is rounded up to the next
// multiple of the base alignment of the structure.
RoundToPow2(size, maxAlignment);
return maxAlignment;
}
// rule 1
if (type.isScalar())
return getBaseAlignmentScalar(type, size);
// rules 2 and 3
if (type.isVector()) {
int scalarAlign = getBaseAlignmentScalar(type, size);
switch (type.getVectorSize()) {
case 2:
size *= 2;
return 2 * scalarAlign;
default:
size *= type.getVectorSize();
return 4 * scalarAlign;
}
}
// rules 5 and 7
if (type.isMatrix()) {
// rule 5: deref to row, not to column, meaning the size of vector is num columns instead of num rows
TType derefType(type, 0, rowMajor);
alignment = getBaseAlignment(derefType, size, dummyStride, std140, rowMajor);
if (std140)
alignment = std::max(baseAlignmentVec4Std140, alignment);
RoundToPow2(size, alignment);
stride = size; // use intra-matrix stride for stride of a just a matrix
if (rowMajor)
size = stride * type.getMatrixRows();
else
size = stride * type.getMatrixCols();
return alignment;
}
assert(0); // all cases should be covered above
size = baseAlignmentVec4Std140;
return baseAlignmentVec4Std140;
}