C++ TType::isImplicitlySizedArray方法代码示例

// Recursively merge the implicit array sizes through the objects' respective type trees.
void TIntermediate::mergeImplicitArraySizes(TType& type, const TType& unitType)
{
    if (type.isImplicitlySizedArray() && unitType.isArray()) {
        int newImplicitArraySize = unitType.isImplicitlySizedArray() ? unitType.getImplicitArraySize() : unitType.getOuterArraySize();
        if (newImplicitArraySize > type.getImplicitArraySize ())
            type.setImplicitArraySize(newImplicitArraySize);
    }

    // Type mismatches are caught and reported after this, just be careful for now.
    if (! type.isStruct() || ! unitType.isStruct() || type.getStruct()->size() != unitType.getStruct()->size())
        return;

    for (int i = 0; i < (int)type.getStruct()->size(); ++i)
        mergeImplicitArraySizes(*(*type.getStruct())[i].type, *(*unitType.getStruct())[i].type);
}

// Recursively figure out how many locations are used up by an input or output type.
// Return the size of type, as measured by "locations".
int TIntermediate::computeTypeLocationSize(const TType& type) const
{
    // "If the declared input is an array of size n and each element takes m locations, it will be assigned m * n 
    // consecutive locations..."
    if (type.isArray()) {
        // TODO: perf: this can be flattened by using getCumulativeArraySize(), and a deref that discards all arrayness
        TType elementType(type, 0);
        if (type.isImplicitlySizedArray()) {
            // TODO: are there valid cases of having an implicitly-sized array with a location?  If so, running this code too early.
            return computeTypeLocationSize(elementType);
        } else
            return type.getOuterArraySize() * computeTypeLocationSize(elementType);
    }

    // "The locations consumed by block and structure members are determined by applying the rules above 
    // recursively..."    
    if (type.isStruct()) {
        int size = 0;
        for (int member = 0; member < (int)type.getStruct()->size(); ++member) {
            TType memberType(type, member);
            size += computeTypeLocationSize(memberType);
        }
        return size;
    }

    // ES: "If a shader input is any scalar or vector type, it will consume a single location."

    // Desktop: "If a vertex shader input is any scalar or vector type, it will consume a single location. If a non-vertex 
    // shader input is a scalar or vector type other than dvec3 or dvec4, it will consume a single location, while 
    // types dvec3 or dvec4 will consume two consecutive locations. Inputs of type double and dvec2 will 
    // consume only a single location, in all stages."
    if (type.isScalar())
        return 1;
    if (type.isVector()) {
        if (language == EShLangVertex && type.getQualifier().isPipeInput())
            return 1;
        if (type.getBasicType() == EbtDouble && type.getVectorSize() > 2)
            return 2;
        else
            return 1;
    }

    // "If the declared input is an n x m single- or double-precision matrix, ...
    // The number of locations assigned for each matrix will be the same as 
    // for an n-element array of m-component vectors..."
    if (type.isMatrix()) {
        TType columnType(type, 0);
        return type.getMatrixCols() * computeTypeLocationSize(columnType);
    }

    assert(0);
    return 1;
}