本文整理匯總了C#中Actor.NewLocation方法的典型用法代碼示例。如果您正苦於以下問題：C# Actor.NewLocation方法的具體用法？C# Actor.NewLocation怎麽用？C# Actor.NewLocation使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Actor的用法示例。
在下文中一共展示了Actor.NewLocation方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的C#代碼示例。
示例1: MatchOpponents
/**
* This will match a mobile opponent (an actor that doesn't yet have a destination) and a
* stationary opponent (an actor that has a destination). The current usage context for this is
* when multiple actors are attackking the stationaryActor.
**/
private void MatchOpponents(Actor mobileActor, Actor stationaryActor, bool prevLocCacheRequired = false)
{
mobileActor.target = stationaryActor;
stationaryActor.target = mobileActor;
//We want to offset the y position of the stacked mobile actor
int randSeed = Random.Range (1, 2) == 1 ? -1 : 1;
stanceOffSetY *= randSeed;
//We want to offset the x position of the stacked mobile actor
float stanceOffSetXLocal = stanceOffSetX * stationaryActor.transform.localScale.x;
Vector3 newVector = new Vector3 ((stationaryActor.endMarker.x + stanceOffSetXLocal), stationaryActor.endMarker.y+stanceOffSetY, stationaryActor.endMarker.z );
Vector3? cachedPrevious = null;
if (prevLocCacheRequired) {
cachedPrevious = mobileActor.prevLoc;
}
mobileActor.NewLocation (newVector);
if (prevLocCacheRequired) {
mobileActor.prevLoc = cachedPrevious.Value;
}
}