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C# Surface.DivideSurface方法代码示例

本文整理汇总了C#中Surface.DivideSurface方法的典型用法代码示例。如果您正苦于以下问题:C# Surface.DivideSurface方法的具体用法?C# Surface.DivideSurface怎么用?C# Surface.DivideSurface使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Surface的用法示例。


在下文中一共展示了Surface.DivideSurface方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: CombineSurface

        /// <summary>
        ///     Combines two surfaces using the operator of this binary expression
        /// </summary>
        /// <param name="leftSurface"></param>
        /// <param name="rightSurface"></param>
        /// <returns></returns>
        private Surface CombineSurface(Surface leftSurface, Surface rightSurface)
        {
            Surface retVal = null;

            switch (Operation)
            {
                case Operator.Add:
                    retVal = leftSurface.AddSurface(rightSurface);
                    break;

                case Operator.Sub:
                    retVal = leftSurface.SubstractSurface(rightSurface);
                    break;

                case Operator.Mult:
                    retVal = leftSurface.MultiplySurface(rightSurface);
                    break;

                case Operator.Div:
                    retVal = leftSurface.DivideSurface(rightSurface);
                    break;
            }

            return retVal;
        }
开发者ID:GautierBerck,项目名称:ERTMSFormalSpecs,代码行数:31,代码来源:BinaryExpression.cs

示例2: combineSurface

        /// <summary>
        ///     Combines two surfaces using the operator of this binary expression
        /// </summary>
        /// <param name="leftSurface"></param>
        /// <param name="rightSurface"></param>
        /// <returns></returns>
        private Surface combineSurface(Surface leftSurface, Surface rightSurface)
        {
            Surface retVal = null;

            switch (Operation)
            {
                case OPERATOR.ADD:
                    retVal = leftSurface.AddSurface(rightSurface);
                    break;

                case OPERATOR.SUB:
                    retVal = leftSurface.SubstractSurface(rightSurface);
                    break;

                case OPERATOR.MULT:
                    retVal = leftSurface.MultiplySurface(rightSurface);
                    break;

                case OPERATOR.DIV:
                    retVal = leftSurface.DivideSurface(rightSurface);
                    break;
            }

            return retVal;
        }
开发者ID:JamesOakey,项目名称:ERTMSFormalSpecs,代码行数:31,代码来源:BinaryExpression.cs


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