C# IGraphics.Translate方法代码示例

 /** Draw the shape with the given offset using IGraphics drawPolyLine.
  *
  * @param graphics  the IGraphics context used to draw the shape
  * @param offsetX   the X amount to offset the shape when drawing
  * @param offsetY   the Y amount to offset the shape when drawing
  */
 public void draw(IGraphics graphics, int offsetX, int offsetY)
 {
     if (_xPoints == null || _yPoints == null)
     // Nothing to draw
     return;
       graphics.Translate(offsetX, offsetY);
       graphics.DrawPolyline(_xPoints, _yPoints, _xPoints.Length);
       graphics.Translate(-offsetX, -offsetY);
 }

        public override void RenderControl(Control c, IGraphics g)
        {
            for (int i = 0; i < styleNames.Count; i++)
            {
                List<Location> locs = styleLocations[i];
                List<Path> paths = stylePaths[i];

                if (styleNames[i] != (string)c.Style)
                    continue;
                if (styleTypes[i] != c.GetType())
                {
                    if ((c.GetType().Assembly == Assembly.GetExecutingAssembly()) || !c.GetType().IsSubclassOf(styleTypes[i]))
                        continue;
                }
                if ((styleStates[i] & c.State) != styleStates[i])
                    continue;

                PatternList plist = styleOperations[i];

                for (int j = 0; j < plist.Count; j++)
                {
                    g.Save();

                    Path path = (paths[j] != null) ? paths[j].Clone() : c.Path.Clone();
                    path.Control = c;

                    if (locs[j] != null)
                    {
                        // This is a little hackish, but I can't think of a better way
                        // Without reworking major chunks of the geometry classes

                        Control tmp = new Control();
                        tmp.Path = path;
                        tmp.Parent = c;
                        path.Control = tmp;

                        Location loc = locs[j].Clone();
                        loc.Control = tmp;

                        g.Translate(loc.RealL, loc.RealT);
                        loc.HandleRel();

                        path = tmp.Path.ClonePixels();
                        tmp.Parent = null;
                    }

                    path.Apply(g);

                    plist[j].Apply(g, path.W, path.H);

                    if (plist[j].Type == PatternType.Fill)
                        g.Fill();
                    else
                        g.Stroke();

                    g.Restore();
                }
            }
        }

        /** Draw this shape so that it touches the left edge of the target shape,
         * or if gap is > 0 then place that many pixels of gap between the two shapes.
         *
         * @param graphics  the IGraphics context used to draw the shape
         * @param target    the target shape on whose left edge this is drawn
         * @param targetOffsetX   the X amount to offset the target shape. Note that
         *              the target shape is placed with the offset and this shape
         *              is placed to the left of it.
         * @param targetOffsetY   the Y amount to offset the target shape
         * @param gap       amount of space between the two shapes.  If zero,
         *                  then the two shapes touch.  If 1, then there is one
         *                  pixel between them, etc.
         * @see #draw
         */
        public void drawLeftOf(IGraphics graphics, DrawShape target, int targetOffsetX, int targetOffsetY, int gap)
        {
            // Note that to get the two shapes to just touch with zero gap, the
              //   value of _rightEdge must be one left of the value of target._leftEdge
              int offsetX = targetOffsetX + target._leftEdge - (_rightEdge + gap + 1);

              graphics.Translate(offsetX, targetOffsetY);
              graphics.DrawPolyline(_xPoints, _yPoints, _xPoints.Length);
              graphics.Translate(-offsetX, -targetOffsetY);
        }