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C++ Menu::Get_Command方法代码示例

本文整理汇总了C++中Menu::Get_Command方法的典型用法代码示例。如果您正苦于以下问题:C++ Menu::Get_Command方法的具体用法?C++ Menu::Get_Command怎么用?C++ Menu::Get_Command使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Menu的用法示例。


在下文中一共展示了Menu::Get_Command方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: Select_Venue

void Command_Processor::Select_Venue()
{
    Menu* menu = new Menu("Select Venue");
    for (int i = 0; i < *nr_venues; ++i)
    {
		menu->Add_Command(venues[i]->Name());
    }

	menu->Add_Command("Cancel");

    const string* venue_name = menu->Get_Command();

    // Find venue with this name
    for (int i = 0; i <= *nr_venues; ++i)
    {
		if (i < *nr_venues)
		{
			if (venues[i]->Name() == *venue_name)
			{
				selected_venue = venues[i];
				command_state = State_Selected;
				return;
			}
		}
		else
		{
			command_state = Initial;
			return;
		}
    }

    // Should never reach this point.
    cout << "Error in Command_Processor::Select_Venue()\n";
}
开发者ID:jimbui,项目名称:project_eight,代码行数:34,代码来源:Command_Processor.cpp

示例2: Select_Venue

	 void CommandProcessor::Select_Venue()
	{
		Menu* menu = new Menu("Select Venue");
		
		for (int i = 0; i < nr_venues; ++i)
		{
			menu->Add_Command(venues[i]->Name());
			
		}

		const string* venue_name = menu->Get_Command();

		// Find Venue with this name
		for (int i = 0; i < nr_venues; ++i)
		{
			if (venues[i]->Name() == *venue_name)
			{
				selected_venue = venues[i];
				//command_state = Venue_Selected; 
				command_state = Venue_Option;
				return;
			}
		}
		// Should never reach this point.
		cout << "Error in Command_Processor::Select_State()\n";
	}
开发者ID:sadhwani,项目名称:Ticket_Booth_0,代码行数:26,代码来源:CommandProcessor.cpp


注:本文中的Menu::Get_Command方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。