本文整理汇总了C++中CGUIControl::IsVisibleFromSkin方法的典型用法代码示例。如果您正苦于以下问题：C++ CGUIControl::IsVisibleFromSkin方法的具体用法？C++ CGUIControl::IsVisibleFromSkin怎么用？C++ CGUIControl::IsVisibleFromSkin使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类CGUIControl的用法示例。
在下文中一共展示了CGUIControl::IsVisibleFromSkin方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: UpdateViewVisibility
void CGUIViewControl::UpdateViewVisibility()
{
// first reset our infomanager cache, as it's likely that the vis conditions
// used for views (i.e. based on contenttype) may have changed
g_infoManager.ResetCache();
m_visibleViews.clear();
for (unsigned int i = 0; i < m_allViews.size(); i++)
{
CGUIControl *view = m_allViews[i];
if (view->HasVisibleCondition())
{
view->UpdateVisibility();
if (view->IsVisibleFromSkin())
m_visibleViews.push_back(view);
}
else
m_visibleViews.push_back(view);
}
}示例2: UpdateViewVisibility
void CGUIViewControl::UpdateViewVisibility()
{
// first reset our infomanager cache, as it's likely that the vis conditions
// used for views (i.e. based on contenttype) may have changed
CGUIInfoManager& infoMgr = CServiceBroker::GetGUI()->GetInfoManager();
infoMgr.ResetCache();
infoMgr.GetInfoProviders().GetGUIControlsInfoProvider().ResetContainerMovingCache();
m_visibleViews.clear();
for (unsigned int i = 0; i < m_allViews.size(); i++)
{
CGUIControl *view = m_allViews[i];
if (view->HasVisibleCondition())
{
view->UpdateVisibility(nullptr);
if (view->IsVisibleFromSkin())
m_visibleViews.push_back(view);
}
else
m_visibleViews.push_back(view);
}
}