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Python Room.roomId方法代码示例

本文整理汇总了Python中room.Room.roomId方法的典型用法代码示例。如果您正苦于以下问题:Python Room.roomId方法的具体用法?Python Room.roomId怎么用?Python Room.roomId使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在room.Room的用法示例。


在下文中一共展示了Room.roomId方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: addRoom

# 需要导入模块: from room import Room [as 别名]
# 或者: from room.Room import roomId [as 别名]
 def addRoom(self, adjRoom, type, direction=NO_DIR):
     # print "Add Room Called"
     # assign the room new coords relative to the adjacent room 
     gridCoord = [0, 0]
     # if the new room is to the west of adjRoom
     if direction == WEST:
         gridCoord[x] = adjRoom.gridCoord[x] - 1
         gridCoord[y] = adjRoom.gridCoord[y]
     # if the new room is to the north of adjRoom
     elif direction == NORTH:
         gridCoord[x] = adjRoom.gridCoord[x]
         gridCoord[y] = adjRoom.gridCoord[y] - 1
     # if the new room is to the east of adjRoom
     elif direction == EAST:
         gridCoord[x] = adjRoom.gridCoord[x] + 1
         gridCoord[y] = adjRoom.gridCoord[y]
     # if the new room is to the south of adjRoom
     elif direction == SOUTH:
         gridCoord[x] = adjRoom.gridCoord[x]
         gridCoord[y] = adjRoom.gridCoord[y] + 1
     
     alreadyExists = False
     for room in self.rooms:
         if room.gridCoord == gridCoord:
             alreadyExists = True
     
     if not alreadyExists:
         # make the room
         newRoom = Room(direction, type, [None, None, None, None], gridCoord)
         newRoom.doors[opposite(direction)] = Door(opposite(direction))
         adjRoom.doors[direction] = Door(direction)
         # update pointers
         if direction != NO_DIR:
             adjRoom.adjRooms[direction] = newRoom
             newRoom.adjRooms[opposite(direction)] = adjRoom
         
         newRoom.roomId = len(Dungeon.floorKeys)
         room = r.randint(0, len(self.rooms) - 1)
         xPos = r.randint(Room.currentRoom.boundingBox[WEST] + Key.keyImg.width/2,
                         Room.currentRoom.boundingBox[EAST] - Key.keyImg.width/2)
         yPos = r.randint(Room.currentRoom.boundingBox[NORTH] + Key.keyImg.width/2,
                         Room.currentRoom.boundingBox[SOUTH] - Key.keyImg.width/2)
         newKey = Key(xPos, yPos, self.rooms[room])
         newRoom.rightKey = newKey
         Dungeon.floorKeys.append(newKey)
         self.rooms.append(newRoom)
         self.linkRooms(newRoom)
     
     return True if not alreadyExists else False
开发者ID:Buzzlet,项目名称:jcpeter-game,代码行数:51,代码来源:dungeon.py


注:本文中的room.Room.roomId方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。