本文整理汇总了C++中eigen::VectorXf::fill方法的典型用法代码示例。如果您正苦于以下问题：C++ VectorXf::fill方法的具体用法？C++ VectorXf::fill怎么用？C++ VectorXf::fill使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类eigen::VectorXf的用法示例。
在下文中一共展示了VectorXf::fill方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: if
float mmf::OptSO3MMFvMF::computeAssignment(uint32_t& N)
{
N = this->cld_.counts().sum();
// Compute log of the cluster weights and push them to GPU
Eigen::VectorXf pi = Eigen::VectorXf::Ones(K()*6)*1000;
std::cout << this->t_ << std::endl;
std::cout<<"counts: "<<this->cld_.counts().transpose()<<std::endl;
if (this->t_ == 0) {
pi.fill(1.);
} else if (this->t_ >24) {
std::cout << "truncating noisy MFs: " << std::endl;
for (uint32_t k=0; k<K()*6; ++k) {
float count = this->cld_.counts().middleRows((k/6)*6,6).sum();
pi(k) = count > 0.10*N ? count : 1.e-20;
std::cout << count << " < " << 0.1*N << std::endl;
}
} else {
// estimate the axis and MF proportions
// pi += this->cld_.counts();
// estimate only the MF proportions
for (uint32_t k=0; k<K()*6; ++k)
pi(k) += this->cld_.counts().middleRows((k/6)*6,6).sum();
if (estimateTau_) {
for (uint32_t k=0; k<K()*6; ++k)
if (this->cld_.counts()(k) == 0) {
taus_(k) = 0.; // uniform
} else {
Eigen::Vector3f mu = Eigen::Vector3f::Zero();
mu((k%6)/2) = (k%6)%2==0?-1.:1.;
mu = Rs_[k/6]*mu;
taus_(k) = jsc::vMF<3>::MLEstimateTau(
this->cld_.xSums().col(k).cast<double>(),
mu.cast<double>(), this->cld_.counts()(k));
}
} else {
taus_.fill(60.);
}
}
std::cout<<"pi: "<<pi.transpose()<<std::endl;
pi = (pi.array() / pi.sum()).array().log();
std::cout<<"pi: "<<pi.transpose()<<std::endl;
if (estimateTau_) {
std::cout << pi.transpose() << std::endl;
std::cout << taus_.transpose() << std::endl;
for (uint32_t k=0; k<K()*6; ++k) {
pi(k) -= jsc::vMF<3>::log2SinhOverZ(taus_(k)) - log(2.*M_PI);
}
}
pi_.set(pi);
Rot2Device();
Eigen::VectorXf residuals = Eigen::VectorXf::Zero(K()*6);
MMFvMFCostFctAssignmentGPU((float*)residuals.data(), d_cost, &N,
d_N_, cld_.d_x(), d_weights_, cld_.d_z(), d_mu_, pi_.data(),
cld_.N(), K());
return residuals.sum();
};