本文整理汇总了C++中state::eos方法的典型用法代码示例。如果您正苦于以下问题：C++ state::eos方法的具体用法？C++ state::eos怎么用？C++ state::eos使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类state的用法示例。
在下文中一共展示了state::eos方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: decode_octal
static CharT decode_octal (state &state_)
{
std::size_t accumulator_ = 0;
CharT ch_ = *state_._curr;
unsigned short count_ = 3;
bool eos_ = false;
for (;;)
{
accumulator_ *= 8;
accumulator_ += ch_ - '0';
--count_;
state_.increment ();
eos_ = state_.eos ();
if (!count_ || eos_) break;
ch_ = *state_._curr;
// Don't consume invalid chars!
if (ch_ < '0' || ch_ > '7')
{
break;
}
}
return static_cast<CharT> (accumulator_);
}示例2: decode_hex
static CharT decode_hex (state &state_)
{
// Skip over 'x'
state_.increment ();
CharT ch_ = 0;
bool eos_ = state_.next (ch_);
if (eos_)
{
// Pointless returning index if at end of string
throw runtime_error ("Unexpected end of regex following \\x.");
}
if (!((ch_ >= '0' && ch_ <= '9') || (ch_ >= 'a' && ch_ <= 'f') ||
(ch_ >= 'A' && ch_ <= 'F')))
{
std::ostringstream ss_;
ss_ << "Illegal char following \\x at index " <<
state_.index () - 1 << '.';
throw runtime_error (ss_.str ().c_str ());
}
std::size_t hex_ = 0;
do
{
hex_ *= 16;
if (ch_ >= '0' && ch_ <= '9')
{
hex_ += ch_ - '0';
}
else if (ch_ >= 'a' && ch_ <= 'f')
{
hex_ += 10 + (ch_ - 'a');
}
else
{
hex_ += 10 + (ch_ - 'A');
}
eos_ = state_.eos ();
if (!eos_)
{
ch_ = *state_._curr;
// Don't consume invalid chars!
if (((ch_ >= '0' && ch_ <= '9') ||
(ch_ >= 'a' && ch_ <= 'f') || (ch_ >= 'A' && ch_ <= 'F')))
{
state_.increment ();
}
else
{
eos_ = true;
}
}
} while (!eos_);
return static_cast<CharT> (hex_);
}