当前位置: 首页>>代码示例>>C++>>正文


C++ TileLayer::getAnimation方法代码示例

本文整理汇总了C++中TileLayer::getAnimation方法的典型用法代码示例。如果您正苦于以下问题:C++ TileLayer::getAnimation方法的具体用法?C++ TileLayer::getAnimation怎么用?C++ TileLayer::getAnimation使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在TileLayer的用法示例。


在下文中一共展示了TileLayer::getAnimation方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: startAnimation

/* ------------------------------------------------------------------------------
 * startAnimation - Attempts to start the next tile in the chained conveyor
 * belt animation.  Returns true if all tiles have been started.  For best
 * results, call this method each time a new screen frame is blitted.
 */
bool ConveyorAnimation::startAnimation() {
    if (this->nextTileToStart >= this->conveyorTiles.size()) {
        return true;
    }

    GridLayer* gl = GridLayer::GetInstance();

    TileLayer* currentTile = NULL;
    if (this->nextTileToStart == 0) {

        // Always start the first tile in the belt.
        TileCoord currentTileCoord = this->conveyorTiles[0];
        currentTile = gl->getTile(currentTileCoord.first, currentTileCoord.second);
        currentTile->getAnimation()->play();
        gl->pushAnimatedTile(currentTile);
        this->nextTileToStart++;

    } else {
        TileCoord currentTileCoord = this->conveyorTiles[this->nextTileToStart-1];
        currentTile = gl->getTile(currentTileCoord.first, currentTileCoord.second);

        if ((currentTile->getAnimation()->getCurrentStill()+1) % 8 == 0) {
            TileCoord tileCoord = this->conveyorTiles[this->nextTileToStart];
            TileLayer* tile = gl->getTile(tileCoord.first, tileCoord.second);
            tile->getAnimation()->play();
            gl->pushAnimatedTile(tile);

            this->nextTileToStart++;
        }
    }

    return (this->nextTileToStart >= this->conveyorTiles.size());

}
开发者ID:,项目名称:,代码行数:39,代码来源:


注:本文中的TileLayer::getAnimation方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。