本文整理汇总了Python中sympy.physics.continuum_mechanics.beam.Beam.join方法的典型用法代码示例。如果您正苦于以下问题：Python Beam.join方法的具体用法？Python Beam.join怎么用？Python Beam.join使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.physics.continuum_mechanics.beam.Beam的用法示例。
在下文中一共展示了Beam.join方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_composite_beam
# 需要导入模块: from sympy.physics.continuum_mechanics.beam import Beam [as 别名]
# 或者: from sympy.physics.continuum_mechanics.beam.Beam import join [as 别名]
def test_composite_beam():
E = Symbol('E')
I = Symbol('I')
b1 = Beam(2, E, 1.5*I)
b2 = Beam(2, E, I)
b = b1.join(b2, "fixed")
b.apply_load(-20, 0, -1)
b.apply_load(80, 0, -2)
b.apply_load(20, 4, -1)
b.bc_slope = [(0, 0)]
b.bc_deflection = [(0, 0)]
assert b.length == 4
assert b.second_moment == Piecewise((1.5*I, x <= 2), (I, x <= 4))
assert b.slope().subs(x, 4) == 120.0/(E*I)
assert b.slope().subs(x, 2) == 80.0/(E*I)
assert int(b.deflection().subs(x, 4).args[0]) == 302 # Coefficient of 1/(E*I)
l = symbols('l', positive=True)
R1, M1, R2, R3, P = symbols('R1 M1 R2 R3 P')
b1 = Beam(2*l, E, I)
b2 = Beam(2*l, E, I)
b = b1.join(b2,"hinge")
b.apply_load(M1, 0, -2)
b.apply_load(R1, 0, -1)
b.apply_load(R2, l, -1)
b.apply_load(R3, 4*l, -1)
b.apply_load(P, 3*l, -1)
b.bc_slope = [(0, 0)]
b.bc_deflection = [(0, 0), (l, 0), (4*l, 0)]
b.solve_for_reaction_loads(M1, R1, R2, R3)
assert b.reaction_loads == {R3: -P/2, R2: -5*P/4, M1: -P*l/4, R1: 3*P/4}
assert b.slope().subs(x, 3*l) == -7*P*l**2/(48*E*I)
assert b.deflection().subs(x, 2*l) == 7*P*l**3/(24*E*I)
assert b.deflection().subs(x, 3*l) == 5*P*l**3/(16*E*I)示例2: test_composite_beam
# 需要导入模块: from sympy.physics.continuum_mechanics.beam import Beam [as 别名]
# 或者: from sympy.physics.continuum_mechanics.beam.Beam import join [as 别名]
def test_composite_beam():
E = Symbol('E')
I = Symbol('I')
b1 = Beam(2, E, 1.5*I)
b2 = Beam(2, E, I)
b = b1.join(b2, "fixed")
b.apply_load(-20, 0, -1)
b.apply_load(80, 0, -2)
b.apply_load(20, 4, -1)
b.bc_slope = [(0, 0)]
b.bc_deflection = [(0, 0)]
assert b.length == 4
assert b.second_moment == Piecewise((1.5*I, x <= 2), (I, x <= 4))
assert b.slope().subs(x, 4) == 120.0/(E*I)
assert b.slope().subs(x, 2) == 80.0/(E*I)
assert int(b.deflection().subs(x, 4).args[0]) == 302 # Coefficient of 1/(E*I)
l = symbols('l', positive=True)
R1, M1, R2, R3, P = symbols('R1 M1 R2 R3 P')
b1 = Beam(2*l, E, I)
b2 = Beam(2*l, E, I)
b = b1.join(b2,"hinge")
b.apply_load(M1, 0, -2)
b.apply_load(R1, 0, -1)
b.apply_load(R2, l, -1)
b.apply_load(R3, 4*l, -1)
b.apply_load(P, 3*l, -1)
b.bc_slope = [(0, 0)]
b.bc_deflection = [(0, 0), (l, 0), (4*l, 0)]
b.solve_for_reaction_loads(M1, R1, R2, R3)
assert b.reaction_loads == {R3: -P/2, R2: -5*P/4, M1: -P*l/4, R1: 3*P/4}
assert b.slope().subs(x, 3*l) == -7*P*l**2/(48*E*I)
assert b.deflection().subs(x, 2*l) == 7*P*l**3/(24*E*I)
assert b.deflection().subs(x, 3*l) == 5*P*l**3/(16*E*I)
# When beams having same second moment are joined.
b1 = Beam(2, 500, 10)
b2 = Beam(2, 500, 10)
b = b1.join(b2, "fixed")
b.apply_load(M1, 0, -2)
b.apply_load(R1, 0, -1)
b.apply_load(R2, 1, -1)
b.apply_load(R3, 4, -1)
b.apply_load(10, 3, -1)
b.bc_slope = [(0, 0)]
b.bc_deflection = [(0, 0), (1, 0), (4, 0)]
b.solve_for_reaction_loads(M1, R1, R2, R3)
assert b.slope() == -2*SingularityFunction(x, 0, 1)/5625 + SingularityFunction(x, 0, 2)/1875\
- 133*SingularityFunction(x, 1, 2)/135000 + SingularityFunction(x, 3, 2)/1000\
- 37*SingularityFunction(x, 4, 2)/67500
assert b.deflection() == -SingularityFunction(x, 0, 2)/5625 + SingularityFunction(x, 0, 3)/5625\
- 133*SingularityFunction(x, 1, 3)/405000 + SingularityFunction(x, 3, 3)/3000\
- 37*SingularityFunction(x, 4, 3)/202500