当前位置: 首页>>代码示例>>Python>>正文


Python Beam.apply_support方法代码示例

本文整理汇总了Python中sympy.physics.continuum_mechanics.beam.Beam.apply_support方法的典型用法代码示例。如果您正苦于以下问题:Python Beam.apply_support方法的具体用法?Python Beam.apply_support怎么用?Python Beam.apply_support使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在sympy.physics.continuum_mechanics.beam.Beam的用法示例。


在下文中一共展示了Beam.apply_support方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_apply_support

# 需要导入模块: from sympy.physics.continuum_mechanics.beam import Beam [as 别名]
# 或者: from sympy.physics.continuum_mechanics.beam.Beam import apply_support [as 别名]
def test_apply_support():
    E = Symbol('E')
    I = Symbol('I')

    b = Beam(4, E, I)
    b.apply_support(0, "cantilever")
    b.apply_load(20, 4, -1)
    M_0, R_0 = symbols('M_0, R_0')
    b.solve_for_reaction_loads(R_0, M_0)
    assert b.slope() == (80*SingularityFunction(x, 0, 1) - 10*SingularityFunction(x, 0, 2)
                + 10*SingularityFunction(x, 4, 2))/(E*I)
    assert b.deflection() == (40*SingularityFunction(x, 0, 2) - 10*SingularityFunction(x, 0, 3)/3
                + 10*SingularityFunction(x, 4, 3)/3)/(E*I)

    b = Beam(30, E, I)
    b.apply_support(10, "pin")
    b.apply_support(30, "roller")
    b.apply_load(-8, 0, -1)
    b.apply_load(120, 30, -2)
    R_10, R_30 = symbols('R_10, R_30')
    b.solve_for_reaction_loads(R_10, R_30)
    assert b.slope() == (-4*SingularityFunction(x, 0, 2) + 3*SingularityFunction(x, 10, 2)
            + 120*SingularityFunction(x, 30, 1) + SingularityFunction(x, 30, 2) + S(4000)/3)/(E*I)
    assert b.deflection() == (4000*x/3 - 4*SingularityFunction(x, 0, 3)/3 + SingularityFunction(x, 10, 3)
            + 60*SingularityFunction(x, 30, 2) + SingularityFunction(x, 30, 3)/3 - 12000)/(E*I)

    P = Symbol('P', positive=True)
    L = Symbol('L', positive=True)
    b = Beam(L, E, I)
    b.apply_support(0, type='fixed')
    b.apply_support(L, type='fixed')
    b.apply_load(-P, L/2, -1)
    R_0, R_L, M_0, M_L = symbols('R_0, R_L, M_0, M_L')
    b.solve_for_reaction_loads(R_0, R_L, M_0, M_L)
    assert b.reaction_loads == {R_0: P/2, R_L: P/2, M_0: -L*P/8, M_L: L*P/8}
开发者ID:cklb,项目名称:sympy,代码行数:37,代码来源:test_beam.py

示例2: test_apply_support

# 需要导入模块: from sympy.physics.continuum_mechanics.beam import Beam [as 别名]
# 或者: from sympy.physics.continuum_mechanics.beam.Beam import apply_support [as 别名]
def test_apply_support():
    E = Symbol('E')
    I = Symbol('I')

    b = Beam(4, E, I)
    b.apply_support(0, "cantilever")
    b.apply_load(20, 4, -1)
    M_0, R_0 = symbols('M_0, R_0')
    b.solve_for_reaction_loads(R_0, M_0)
    assert b.slope() == (80*SingularityFunction(x, 0, 1) - 10*SingularityFunction(x, 0, 2)
                + 10*SingularityFunction(x, 4, 2))/(E*I)
    assert b.deflection() == (40*SingularityFunction(x, 0, 2) - 10*SingularityFunction(x, 0, 3)/3
                + 10*SingularityFunction(x, 4, 3)/3)/(E*I)

    b = Beam(30, E, I)
    b.apply_support(10, "pin")
    b.apply_support(30, "roller")
    b.apply_load(-8, 0, -1)
    b.apply_load(120, 30, -2)
    R_10, R_30 = symbols('R_10, R_30')
    b.solve_for_reaction_loads(R_10, R_30)
    assert b.slope() == (-4*SingularityFunction(x, 0, 2) + 3*SingularityFunction(x, 10, 2)
            + 120*SingularityFunction(x, 30, 1) + SingularityFunction(x, 30, 2) + 4000/3)/(E*I)
    assert b.deflection() == (4000*x/3 - 4*SingularityFunction(x, 0, 3)/3 + SingularityFunction(x, 10, 3)
            + 60*SingularityFunction(x, 30, 2) + SingularityFunction(x, 30, 3)/3 - 12000)/(E*I)
开发者ID:KonstantinTogoi,项目名称:sympy,代码行数:27,代码来源:test_beam.py


注:本文中的sympy.physics.continuum_mechanics.beam.Beam.apply_support方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。