本文整理汇总了Python中sympy.assumptions.Q.finite方法的典型用法代码示例。如果您正苦于以下问题：Python Q.finite方法的具体用法？Python Q.finite怎么用？Python Q.finite使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类sympy.assumptions.Q的用法示例。
在下文中一共展示了Q.finite方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: Mul
# 需要导入模块: from sympy.assumptions import Q [as 别名]
# 或者: from sympy.assumptions.Q import finite [as 别名]
def Mul(expr, assumptions):
"""
Return True if expr is bounded, False if not and None if unknown.
Truth Table:
+---+---+---+--------+
| | | | |
| | B | U | ? |
| | | | |
+---+---+---+---+----+
| | | | | |
| | | | s | /s |
| | | | | |
+---+---+---+---+----+
| | | | |
| B | B | U | ? |
| | | | |
+---+---+---+---+----+
| | | | | |
| U | | U | U | ? |
| | | | | |
+---+---+---+---+----+
| | | | |
| ? | | | ? |
| | | | |
+---+---+---+---+----+
* B = Bounded
* U = Unbounded
* ? = unknown boundedness
* s = signed (hence nonzero)
* /s = not signed
"""
result = True
for arg in expr.args:
_bounded = ask(Q.finite(arg), assumptions)
if _bounded:
continue
elif _bounded is None:
if result is None:
return None
if ask(Q.nonzero(arg), assumptions) is None:
return None
if result is not False:
result = None
else:
result = False
return result示例2: Pow
# 需要导入模块: from sympy.assumptions import Q [as 别名]
# 或者: from sympy.assumptions.Q import finite [as 别名]
def Pow(expr, assumptions):
"""
Unbounded ** NonZero -> Unbounded
Bounded ** Bounded -> Bounded
Abs()<=1 ** Positive -> Bounded
Abs()>=1 ** Negative -> Bounded
Otherwise unknown
"""
base_bounded = ask(Q.finite(expr.base), assumptions)
exp_bounded = ask(Q.finite(expr.exp), assumptions)
if base_bounded is None and exp_bounded is None: # Common Case
return None
if base_bounded is False and ask(Q.nonzero(expr.exp), assumptions):
return False
if base_bounded and exp_bounded:
return True
if (abs(expr.base) <= 1) == True and ask(Q.positive(expr.exp), assumptions):
return True
if (abs(expr.base) >= 1) == True and ask(Q.negative(expr.exp), assumptions):
return True
if (abs(expr.base) >= 1) == True and exp_bounded is False:
return False
return None示例3: Symbol
# 需要导入模块: from sympy.assumptions import Q [as 别名]
# 或者: from sympy.assumptions.Q import finite [as 别名]
def Symbol(expr, assumptions):
"""
Handles Symbol.
Examples
========
>>> from sympy import Symbol, Q
>>> from sympy.assumptions.handlers.calculus import AskFiniteHandler
>>> from sympy.abc import x
>>> a = AskFiniteHandler()
>>> a.Symbol(x, Q.positive(x)) == None
True
>>> a.Symbol(x, Q.finite(x))
True
"""
if Q.finite(expr) in conjuncts(assumptions):
return True
return None示例4: Add
# 需要导入模块: from sympy.assumptions import Q [as 别名]
# 或者: from sympy.assumptions.Q import finite [as 别名]
def Add(expr, assumptions):
"""
Return True if expr is bounded, False if not and None if unknown.
Truth Table:
+-------+-----+-----------+-----------+
| | | | |
| | B | U | ? |
| | | | |
+-------+-----+---+---+---+---+---+---+
| | | | | | | | |
| | |'+'|'-'|'x'|'+'|'-'|'x'|
| | | | | | | | |
+-------+-----+---+---+---+---+---+---+
| | | | |
| B | B | U | ? |
| | | | |
+---+---+-----+---+---+---+---+---+---+
| | | | | | | | | |
| |'+'| | U | ? | ? | U | ? | ? |
| | | | | | | | | |
| +---+-----+---+---+---+---+---+---+
| | | | | | | | | |
| U |'-'| | ? | U | ? | ? | U | ? |
| | | | | | | | | |
| +---+-----+---+---+---+---+---+---+
| | | | | |
| |'x'| | ? | ? |
| | | | | |
+---+---+-----+---+---+---+---+---+---+
| | | | |
| ? | | | ? |
| | | | |
+-------+-----+-----------+---+---+---+
* 'B' = Bounded
* 'U' = Unbounded
* '?' = unknown boundedness
* '+' = positive sign
* '-' = negative sign
* 'x' = sign unknown
|
* All Bounded -> True
* 1 Unbounded and the rest Bounded -> False
* >1 Unbounded, all with same known sign -> False
* Any Unknown and unknown sign -> None
* Else -> None
When the signs are not the same you can have an undefined
result as in oo - oo, hence 'bounded' is also undefined.
"""
sign = -1 # sign of unknown or infinite
result = True
for arg in expr.args:
_bounded = ask(Q.finite(arg), assumptions)
if _bounded:
continue
s = ask(Q.positive(arg), assumptions)
# if there has been more than one sign or if the sign of this arg
# is None and Bounded is None or there was already
# an unknown sign, return None
if sign != -1 and s != sign or \
s is None and (s == _bounded or s == sign):
return None
else:
sign = s
# once False, do not change
if result is not False:
result = _bounded
return result示例5: log
# 需要导入模块: from sympy.assumptions import Q [as 别名]
# 或者: from sympy.assumptions.Q import finite [as 别名]
def log(expr, assumptions):
return ask(Q.finite(expr.args[0]), assumptions)