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Python QMap.upperBound方法代码示例

本文整理汇总了Python中pyqtcore.QMap.upperBound方法的典型用法代码示例。如果您正苦于以下问题:Python QMap.upperBound方法的具体用法?Python QMap.upperBound怎么用?Python QMap.upperBound使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在pyqtcore.QMap的用法示例。


在下文中一共展示了QMap.upperBound方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: GidMapper

# 需要导入模块: from pyqtcore import QMap [as 别名]
# 或者: from pyqtcore.QMap import upperBound [as 别名]
class GidMapper():
    ##
    # Default constructor. Use \l insert to initialize the gid mapper
    # incrementally.
    ##
    def __init__(self, *args):
        self.mInvalidTile = None
        self.mTilesetColumnCounts = QMap()
        self.mFirstGidToTileset = QMap()
        if len(args)==1:
            ##
            # Constructor that initializes the gid mapper using the given \a tilesets.
            ##
            firstGid = 1
            tilesets = args[0]
            for tileset in tilesets:
                self.insert(firstGid, tileset)
                firstGid += tileset.tileCount()

    ##
    # Insert the given \a tileset with \a firstGid as its first global ID.
    ##
    def insert(self, firstGid, tileset):
        self.mFirstGidToTileset.insert(firstGid, tileset)

    ##
    # Clears the gid mapper, so that it can be reused.
    ##
    def clear(self):
        self.mFirstGidToTileset.clear()

    ##
    # Returns True when no tilesets are known to this gid mapper.
    ##
    def isEmpty(self):
        return self.mFirstGidToTileset.isEmpty()

    ##
    # Returns the GID of the invalid tile in case decodeLayerData() returns
    # the InvalidTile error.
    ##
    def invalidTile(self):
        return self.mInvalidTile

    ##
    # Returns the cell data matched by the given \a gid. The \a ok parameter
    # indicates whether an error occurred.
    ##
    def gidToCell(self, gid):
        result = Cell()
        # Read out the flags
        result.flippedHorizontally = (gid & FlippedHorizontallyFlag)
        result.flippedVertically = (gid & FlippedVerticallyFlag)
        result.flippedAntiDiagonally = (gid & FlippedAntiDiagonallyFlag)
        # Clear the flags
        gid &= ~(FlippedHorizontallyFlag |
                 FlippedVerticallyFlag |
                 FlippedAntiDiagonallyFlag)
        if (gid == 0):
            ok = True
        elif (self.isEmpty()):
            ok = False
        else:
            # Find the tileset containing this tile
            index = self.mFirstGidToTileset.upperBound(gid)
            if index==0:
                ok = False
            else:
                item = self.mFirstGidToTileset.itemByIndex(index-1)
                # Navigate one tileset back since upper bound finds the next
                tileId = gid - item[0]
                tileset = item[1]

                columnCount = self.mTilesetColumnCounts.value(tileset, 0)
                if (columnCount > 0 and columnCount != tileset.columnCount()):
                    # Correct tile index for changes in image width
                    row = int(tileId / columnCount)
                    column = int(tileId % columnCount)
                    tileId = row * tileset.columnCount() + column
                result.tile = tileset.tileAt(tileId)
                ok = True

        return result, ok

    ##
    # Returns the global tile ID for the given \a cell. Returns 0 when the
    # cell is empty or when its tileset isn't known.
    ##
    def cellToGid(self, cell):
        if (cell.isEmpty()):
            return 0
        tileset = cell.tile.tileset()
        # Find the first GID for the tileset
        for item in self.mFirstGidToTileset:
            if item[1] == tileset:
                gid = item[0] + cell.tile.id()
                if (cell.flippedHorizontally):
                    gid |= FlippedHorizontallyFlag
                if (cell.flippedVertically):
                    gid |= FlippedVerticallyFlag
#.........这里部分代码省略.........
开发者ID:theall,项目名称:Python-Tiled,代码行数:103,代码来源:gidmapper.py


注:本文中的pyqtcore.QMap.upperBound方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。