本文整理汇总了Python中lifelines.estimation.CoxPHFitter.predict_log_hazard_relative_to_mean方法的典型用法代码示例。如果您正苦于以下问题：Python CoxPHFitter.predict_log_hazard_relative_to_mean方法的具体用法？Python CoxPHFitter.predict_log_hazard_relative_to_mean怎么用？Python CoxPHFitter.predict_log_hazard_relative_to_mean使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类lifelines.estimation.CoxPHFitter的用法示例。
在下文中一共展示了CoxPHFitter.predict_log_hazard_relative_to_mean方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_predict_log_hazard_relative_to_mean_without_normalization
# 需要导入模块: from lifelines.estimation import CoxPHFitter [as 别名]
# 或者: from lifelines.estimation.CoxPHFitter import predict_log_hazard_relative_to_mean [as 别名]
def test_predict_log_hazard_relative_to_mean_without_normalization(self, rossi):
cox = CoxPHFitter(normalize=False)
cox.fit(rossi, 'week', 'arrest')
log_relative_hazards = cox.predict_log_hazard_relative_to_mean(rossi)
means = rossi.mean(0).to_frame().T
assert cox.predict_partial_hazard(means).values[0][0] != 1.0
assert_frame_equal(log_relative_hazards, np.log(cox.predict_partial_hazard(rossi) / cox.predict_partial_hazard(means).squeeze()))示例2: test_predict_log_hazard_relative_to_mean_with_normalization
# 需要导入模块: from lifelines.estimation import CoxPHFitter [as 别名]
# 或者: from lifelines.estimation.CoxPHFitter import predict_log_hazard_relative_to_mean [as 别名]
def test_predict_log_hazard_relative_to_mean_with_normalization(self, rossi):
cox = CoxPHFitter(normalize=True)
cox.fit(rossi, 'week', 'arrest')
# they are equal because the data is normalized, so the mean of the covarites is all 0,
# thus exp(beta * 0) == 1, so exp(beta * X)/exp(beta * 0) = exp(beta * X)
assert_frame_equal(cox.predict_log_hazard_relative_to_mean(rossi), np.log(cox.predict_partial_hazard(rossi)))