本文整理汇总了C#中ShadingState.getTrianglePoints方法的典型用法代码示例。如果您正苦于以下问题：C# ShadingState.getTrianglePoints方法的具体用法？C# ShadingState.getTrianglePoints怎么用？C# ShadingState.getTrianglePoints使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类ShadingState的用法示例。
在下文中一共展示了ShadingState.getTrianglePoints方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: getRadiance
public Color getRadiance(ShadingState state)
{
Point3[] p = new Point3[3];
if (!state.getTrianglePoints(p))
return getFillColor(state);
// transform points into camera space
Point3 center = state.getPoint();
Matrix4 w2c = state.getWorldToCamera();
center = w2c.transformP(center);
for (int i = 0; i < 3; i++)
p[i] = w2c.transformP(state.getInstance().transformObjectToWorld(p[i]));
float cn = 1.0f / (float)Math.Sqrt(center.x * center.x + center.y * center.y + center.z * center.z);
for (int i = 0, i2 = 2; i < 3; i2 = i, i++)
{
// compute orthogonal projection of the shading point onto each
// triangle edge as in:
// http://mathworld.wolfram.com/Point-LineDistance3-Dimensional.html
float t = (center.x - p[i].x) * (p[i2].x - p[i].x);
t += (center.y - p[i].y) * (p[i2].y - p[i].y);
t += (center.z - p[i].z) * (p[i2].z - p[i].z);
t /= p[i].distanceToSquared(p[i2]);
float projx = (1 - t) * p[i].x + t * p[i2].x;
float projy = (1 - t) * p[i].y + t * p[i2].y;
float projz = (1 - t) * p[i].z + t * p[i2].z;
float n = 1.0f / (float)Math.Sqrt(projx * projx + projy * projy + projz * projz);
// check angular width
float dot = projx * center.x + projy * center.y + projz * center.z;
if (dot * n * cn >= cosWidth)
return getLineColor(state);
}
return getFillColor(state);
}