本文整理汇总了C#中AssetManager.Update方法的典型用法代码示例。如果您正苦于以下问题：C# AssetManager.Update方法的具体用法？C# AssetManager.Update怎么用？C# AssetManager.Update使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类AssetManager的用法示例。
在下文中一共展示了AssetManager.Update方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: UpdateAsset
public void UpdateAsset(string title, string filename, long contentid, int languageId, byte[] filestream, ContentMetaData[] potentialMeta)
{
try
{
assetManager = new AssetManager();
assetManager.ContentLanguage = languageId;
if (string.IsNullOrEmpty(userauthHeader.AuthenticationToken))
throw new SoapException("User not logged in", SoapException.ClientFaultCode);
this.ImpersonateUser(userauthHeader.AuthenticationToken, assetManager.RequestInformation);
ContentAssetData contentassetdata = assetManager.GetItem(contentid, true);
if (contentassetdata == null)
throw new SoapException("Error Updating Asset", SoapException.ClientFaultCode);
contentassetdata.Title = title;
contentassetdata.File = filestream;
contentassetdata.AssetData.FileName = filename;
contentassetdata.LanguageId = languageId;
contentassetdata.MetaData = potentialMeta;
assetManager.Update(contentassetdata);
}
catch (Exception ex)
{
throw new SoapException("Error updating an asset:" + ex.Message, SoapException.ClientFaultCode);
}
}示例2: GetAssetContentQuickLink
public string GetAssetContentQuickLink(string filename, string title, int languageid, long contentid, long folderid, byte[] filestream)
{
if (string.IsNullOrEmpty(userauthHeader.AuthenticationToken))
throw new SoapException("User not logged in", SoapException.ClientFaultCode);
assetManager = new AssetManager();
assetManager.ContentLanguage = languageid;
this.ImpersonateUser(userauthHeader.AuthenticationToken, assetManager.RequestInformation);
if (contentid > 0)
{
ContentAssetData contentassetdata = assetManager.GetItem(contentid, true);
if (contentassetdata == null)
throw new SoapException("Error Updating Asset", SoapException.ClientFaultCode);
contentassetdata.Title = title;
contentassetdata.File = filestream;
contentassetdata.AssetData.FileName = filename;
contentassetdata.LanguageId = languageid;
return assetManager.GetItem((assetManager.Update(contentassetdata).Id)).Quicklink;
}
else
{
ContentAssetData contentassetdata = new ContentAssetData()
{
FolderId = folderid,
Title = title,
File = filestream,
LanguageId = languageid,
AssetData = new AssetData { FileName = filename }
};
return assetManager.GetItem((assetManager.Add(contentassetdata).Id)).Quicklink;
}
}