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C++ Objective::GetNeighbor方法代码示例

本文整理汇总了C++中Objective::GetNeighbor方法的典型用法代码示例。如果您正苦于以下问题:C++ Objective::GetNeighbor方法的具体用法?C++ Objective::GetNeighbor怎么用?C++ Objective::GetNeighbor使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Objective的用法示例。


在下文中一共展示了Objective::GetNeighbor方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: SendSupply

// This sends supply from s to d, subtracting from losses and adding to it's supply traffic field
// Updates values to amount which actually made it. returns 0 if none made it.
int SendSupply (Objective s, Objective d, int *supply, int *fuel)
	{
	Objective	c;
	PathClass	path;
	int			i,l,n,loss,type;

	if (!*supply && !*fuel)
		return 0;
	if (GetObjectivePath(&path,s,d,Foot,s->GetTeam(),PATH_MARINE) < 1)
		return 0;

	c = s;
	loss = 0;
	AddSupply(s,*supply/10,*fuel/10);
	for (i=0; i<path.GetLength(); i++)
		{
		n = path.GetDirection(i);
		c = c->GetNeighbor(n);
		type = c->GetType();
		if (type == TYPE_ROAD || type == TYPE_INTERSECT || type == TYPE_RAILROAD || type == TYPE_BRIDGE)
			{
			AddSupply(c,*supply/10,*fuel/10);
			l = c->GetObjectiveSupplyLosses() + 2;		// Automatic loss rate of 2% per objective
			*supply = *supply*(100-l)/100;
			*fuel = *fuel*(100-l)/100;
			}
		if (!*supply && !*fuel)
			return 0;
		}
	return 1;
	}
开发者ID:FreeFalcon,项目名称:freefalcon-central,代码行数:33,代码来源:supply.cpp


注:本文中的Objective::GetNeighbor方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。