本文整理汇总了C++中House::OverlapCalc方法的典型用法代码示例。如果您正苦于以下问题:C++ House::OverlapCalc方法的具体用法?C++ House::OverlapCalc怎么用?C++ House::OverlapCalc使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类House
的用法示例。
在下文中一共展示了House::OverlapCalc方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: mouseButton
//.........这里部分代码省略.........
if (570 <= x <= 690)
{
stage = FOUND;
lightPlace = 0;
}
if (740 <= x <= 860)
{
stage = OVERLAPS;
lightPlace = 0;
}
}
break;
case OVERLAPS:
if (0 <= x <= 450)
{
if (100 <= y <= 200)
{
CalcObject.overlapType = panel;
lightPlace = 5;
}
if (200 < y <= 300)
{
CalcObject.overlapType = monolith;
lightPlace = 3;
}
if (300 < y <= 400)
{
CalcObject.overlapType = wood;
lightPlace = 1;
}
}
if (20 <= y <= 80)
{
CalcObject.OverlapCalc(CalcObject.overlapType);
if (570 <= x <= 690)
{
stage = WALLS;
lightPlace = 0;
}
if (740 <= x <= 860)
{
stage = ROOFS;
lightPlace = 0;
}
}
break;
case ROOFS:
if (KindOf == house || KindOf == office)
{
if (0 <= x <= 450)
{
if (100 <= y <= 200)
{
CalcObject.roofType = hipBitTile;
lightPlace = 5;
}
if (200 < y <= 300)
{
CalcObject.roofType = hipTile;
lightPlace = 3;
}
if (300 < y <= 400)
{
CalcObject.roofType = flat;
lightPlace = 1;
}