本文整理汇总了C++中GrFragmentProcessor::numTransforms方法的典型用法代码示例。如果您正苦于以下问题：C++ GrFragmentProcessor::numTransforms方法的具体用法？C++ GrFragmentProcessor::numTransforms怎么用？C++ GrFragmentProcessor::numTransforms使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类GrFragmentProcessor的用法示例。
在下文中一共展示了GrFragmentProcessor::numTransforms方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: isEqual
bool GrFragmentProcessor::isEqual(const GrFragmentProcessor& that,
bool ignoreCoordTransforms) const {
if (this->classID() != that.classID() ||
!this->hasSameTextureAccesses(that)) {
return false;
}
if (ignoreCoordTransforms) {
if (this->numTransforms() != that.numTransforms()) {
return false;
}
} else if (!this->hasSameTransforms(that)) {
return false;
}
if (!this->onIsEqual(that)) {
return false;
}
if (this->numChildProcessors() != that.numChildProcessors()) {
return false;
}
for (int i = 0; i < this->numChildProcessors(); ++i) {
if (!this->childProcessor(i).isEqual(that.childProcessor(i), ignoreCoordTransforms)) {
return false;
}
}
return true;
}示例2: hasSameTransforms
bool GrFragmentProcessor::hasSameTransforms(const GrFragmentProcessor& that) const {
if (this->numTransforms() != that.numTransforms()) {
return false;
}
int count = this->numTransforms();
for (int i = 0; i < count; ++i) {
if (this->coordTransform(i) != that.coordTransform(i)) {
return false;
}
}
return true;
}