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C++ FilterContext::getBundle方法代码示例

本文整理汇总了C++中FilterContext::getBundle方法的典型用法代码示例。如果您正苦于以下问题:C++ FilterContext::getBundle方法的具体用法?C++ FilterContext::getBundle怎么用?C++ FilterContext::getBundle使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在FilterContext的用法示例。


在下文中一共展示了FilterContext::getBundle方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: evaluate

		BundleFilter::ACTION SecurityFilter::evaluate(const FilterContext &context) const throw ()
		{
#ifdef IBRDTN_SUPPORT_BSP
			switch (_mode)
			{
				default:
					break;

				case VERIFY_AUTH:
				{
					try {
						// extract bundle from context
						const dtn::data::Bundle &bundle = context.getBundle();

						// check if at least one BAB is present
						if (std::count(bundle.begin(), bundle.end(), dtn::security::BundleAuthenticationBlock::BLOCK_TYPE) > 0)
						{
							if (_positive_action != BundleFilter::PASS) return _positive_action;
						}
						else
						{
							if (_negative_action != BundleFilter::PASS) return _negative_action;
						}
					} catch (const FilterException&) {
						// necessary bundle object is not present - abort the chain
						return BundleFilter::PASS;
					}
					break;
				}

				case VERIFY_INTEGRITY:
				{
					try {
						// extract bundle from context
						const dtn::data::Bundle &bundle = context.getBundle();

						// check if at least one PIB is present
						if (std::count(bundle.begin(), bundle.end(), dtn::security::PayloadIntegrityBlock::BLOCK_TYPE) > 0)
						{
							if (_positive_action != BundleFilter::PASS) return _positive_action;
						}
						else
						{
							if (_negative_action != BundleFilter::PASS) return _negative_action;
						}
					} catch (const FilterException&) {
						// necessary bundle object is not present - abort the chain
						return BundleFilter::PASS;
					}
					break;
				}

				case VERIFY_CONFIDENTIALITY:
				{
					try {
						// extract bundle from context
						const dtn::data::Bundle &bundle = context.getBundle();

						// check if at least one PCB is present
						if (std::count(bundle.begin(), bundle.end(), dtn::security::PayloadConfidentialBlock::BLOCK_TYPE) > 0)
						{
							if (_positive_action != BundleFilter::PASS) return _positive_action;
						}
						else
						{
							if (_negative_action != BundleFilter::PASS) return _negative_action;
						}
					} catch (const FilterException&) {
						// necessary bundle object is not present - abort the chain
						return BundleFilter::PASS;
					}
					break;
				}
			}
#else
			// without BSP support we can not execute any security check
			// therefore we always proceed as if the check were successful and
			// return with the positive action
			return _positive_action;
#endif

			// forward call to the next filter or return with the default action
			return BundleFilter::evaluate(context);
		}
开发者ID:Timothyboy2015,项目名称:ibrdtn,代码行数:84,代码来源:SecurityFilter.cpp


注:本文中的FilterContext::getBundle方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。