本文整理汇总了C++中EntityTreePointer::hasEntitiesDeletedSince方法的典型用法代码示例。如果您正苦于以下问题:C++ EntityTreePointer::hasEntitiesDeletedSince方法的具体用法?C++ EntityTreePointer::hasEntitiesDeletedSince怎么用?C++ EntityTreePointer::hasEntitiesDeletedSince使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类EntityTreePointer
的用法示例。
在下文中一共展示了EntityTreePointer::hasEntitiesDeletedSince方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: hasSpecialPacketsToSend
// EntityServer will use the "special packets" to send list of recently deleted entities
bool EntityServer::hasSpecialPacketsToSend(const SharedNodePointer& node) {
bool shouldSendDeletedEntities = false;
// check to see if any new entities have been added since we last sent to this node...
EntityNodeData* nodeData = static_cast<EntityNodeData*>(node->getLinkedData());
if (nodeData) {
quint64 deletedEntitiesSentAt = nodeData->getLastDeletedEntitiesSentAt();
EntityTreePointer tree = std::static_pointer_cast<EntityTree>(_tree);
shouldSendDeletedEntities = tree->hasEntitiesDeletedSince(deletedEntitiesSentAt);
}
return shouldSendDeletedEntities;
}
示例2: hasSpecialPacketsToSend
// EntityServer will use the "special packets" to send list of recently deleted entities
bool EntityServer::hasSpecialPacketsToSend(const SharedNodePointer& node) {
bool shouldSendDeletedEntities = false;
// check to see if any new entities have been added since we last sent to this node...
EntityNodeData* nodeData = static_cast<EntityNodeData*>(node->getLinkedData());
if (nodeData) {
quint64 deletedEntitiesSentAt = nodeData->getLastDeletedEntitiesSentAt();
EntityTreePointer tree = std::static_pointer_cast<EntityTree>(_tree);
shouldSendDeletedEntities = tree->hasEntitiesDeletedSince(deletedEntitiesSentAt);
#ifdef EXTRA_ERASE_DEBUGGING
if (shouldSendDeletedEntities) {
int elapsed = usecTimestampNow() - deletedEntitiesSentAt;
qDebug() << "shouldSendDeletedEntities to node:" << node->getUUID() << "deletedEntitiesSentAt:" << deletedEntitiesSentAt << "elapsed:" << elapsed;
}
#endif
}
return shouldSendDeletedEntities;
}