本文整理匯總了Java中net.minecraft.util.MathHelper.floor_double_long方法的典型用法代碼示例。如果您正苦於以下問題：Java MathHelper.floor_double_long方法的具體用法？Java MathHelper.floor_double_long怎麽用？Java MathHelper.floor_double_long使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類net.minecraft.util.MathHelper的用法示例。
在下文中一共展示了MathHelper.floor_double_long方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: generateNoiseOctaves
import net.minecraft.util.MathHelper; //導入方法依賴的package包/類
/**
* pars:(par2,3,4=noiseOffset ; so that adjacent noise segments connect) (pars5,6,7=x,y,zArraySize),(pars8,10,12 =
* x,y,z noiseScale)
*/
public double[] generateNoiseOctaves(double[] p_76304_1_, int p_76304_2_, int p_76304_3_, int p_76304_4_, int p_76304_5_, int p_76304_6_, int p_76304_7_, double p_76304_8_, double p_76304_10_, double p_76304_12_)
{
if (p_76304_1_ == null)
{
p_76304_1_ = new double[p_76304_5_ * p_76304_6_ * p_76304_7_];
}
else
{
for (int i = 0; i < p_76304_1_.length; ++i)
{
p_76304_1_[i] = 0.0D;
}
}
double d3 = 1.0D;
for (int j = 0; j < this.octaves; ++j)
{
double d0 = (double)p_76304_2_ * d3 * p_76304_8_;
double d1 = (double)p_76304_3_ * d3 * p_76304_10_;
double d2 = (double)p_76304_4_ * d3 * p_76304_12_;
long k = MathHelper.floor_double_long(d0);
long l = MathHelper.floor_double_long(d2);
d0 = d0 - (double)k;
d2 = d2 - (double)l;
k = k % 16777216L;
l = l % 16777216L;
d0 = d0 + (double)k;
d2 = d2 + (double)l;
this.generatorCollection[j].populateNoiseArray(p_76304_1_, d0, d1, d2, p_76304_5_, p_76304_6_, p_76304_7_, p_76304_8_ * d3, p_76304_10_ * d3, p_76304_12_ * d3, d3);
d3 /= 2.0D;
}
return p_76304_1_;
}
示例2: lfloor
import net.minecraft.util.MathHelper; //導入方法依賴的package包/類
public static long lfloor(double p_lfloor_0_)
{
return MathHelper.floor_double_long(p_lfloor_0_);
}