Java.util.Stack类的subList()方法用于返回此Stack部分在指定的fromIndex(包括)和toIndex(不包括)之间的视图。 (如果fromIndex和toIndex相等,则返回的Stack为空。)
返回的堆栈由该堆栈支持,因此返回的堆栈中的非结构更改会反映在此堆栈中,反之亦然。返回的堆栈支持所有可选的堆栈操作。
用法:
public Stack subList(int fromIndex, int toIndex)
参数:此方法将以下参数作为参数。
- fromIndex –subList的低端点(包括端点)
- toIndex –subList的高端端点(不包括)
返回值:此方法返回此Stack中指定范围的视图。
异常:此方法引发以下异常。
- IndexOutOfBoundsException –如果端点索引值超出范围(fromIndex大小)
- IllegalArgumentException –如果端点索引不正确(fromIndex> toIndex)
以下示例说明了subList()方法。
示例1:
// Java program to demonstrate
// subList() method
// for String value
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
// Creating object of Stack<Integer>
Stack<String>
stack = new Stack<String>();
// Populating stack1
stack.add("A");
stack.add("B");
stack.add("C");
stack.add("D");
stack.add("E");
// print stack
System.out.println("Original stack: "
+ stack);
// getting the subList
// using subList() method
List<String> stack2 = stack.subList(2, 4);
// print the subList
System.out.println("SubStack of stack: "
+ stack2);
}
catch (Exception e) {
System.out.println(e);
}
}
}
输出:
Original stack: [A, B, C, D, E] SubStack of stack: [C, D]
示例2:对于IndexOutOfBoundsException
// Java program to demonstrate
// subList() method
// for IndexOutOfBoundsException
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
// Creating object of Stack<Integer>
Stack<String>
stack = new Stack<String>();
// Populating stack1
stack.add("A");
stack.add("B");
stack.add("C");
stack.add("D");
stack.add("E");
// print stack
System.out.println("Original stack: "
+ stack);
// getting the subList
// using subList() method
System.out.println("\nEnd index value is out of range");
List<String> stack2 = stack.subList(2, 7);
// print the subList
System.out.println("SubStack of stack: "
+ stack2);
}
catch (Exception e) {
System.out.println(e);
}
}
}
输出:
Original stack: [A, B, C, D, E] End index value is out of range java.lang.IndexOutOfBoundsException: toIndex = 7
示例3:对于IllegalArgumentException
// Java program to demonstrate
// subList() method
// for IllegalArgumentException
import java.util.*;
public class GFG1 {
public static void main(String[] argv) throws Exception
{
try {
// Creating object of Stack<Integer>
Stack<String>
stack = new Stack<String>();
// Populating stack1
stack.add("A");
stack.add("B");
stack.add("C");
stack.add("D");
stack.add("E");
// print stack
System.out.println("Original stack: "
+ stack);
// getting the subList
// using subList() method
System.out.println("\nEndpoint indices "
+ "are out of order"
+ " (fromIndex > toIndex)");
List<String> stack2 = stack.subList(7, 2);
// print the subList
System.out.println("SubStack of stack: "
+ stack2);
}
catch (Exception e) {
System.out.println(e);
}
}
}
输出:
Original stack: [A, B, C, D, E] Endpoint indices are out of order (fromIndex > toIndex) java.lang.IllegalArgumentException: fromIndex(7) > toIndex(2)
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注:本文由纯净天空筛选整理自Code_r大神的英文原创作品 Stack subList() method in Java with Example。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。