Java.util.Stack類的subList()方法用於返回此Stack部分在指定的fromIndex(包括)和toIndex(不包括)之間的視圖。 (如果fromIndex和toIndex相等,則返回的Stack為空。)
返回的堆棧由該堆棧支持,因此返回的堆棧中的非結構更改會反映在此堆棧中,反之亦然。返回的堆棧支持所有可選的堆棧操作。
用法:
public Stack subList(int fromIndex, int toIndex)
參數:此方法將以下參數作為參數。
- fromIndex –subList的低端點(包括端點)
- toIndex –subList的高端端點(不包括)
返回值:此方法返回此Stack中指定範圍的視圖。
異常:此方法引發以下異常。
- IndexOutOfBoundsException –如果端點索引值超出範圍(fromIndex大小)
- IllegalArgumentException –如果端點索引不正確(fromIndex> toIndex)
以下示例說明了subList()方法。
示例1:
// Java program to demonstrate
// subList() method
// for String value
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
// Creating object of Stack<Integer>
Stack<String>
stack = new Stack<String>();
// Populating stack1
stack.add("A");
stack.add("B");
stack.add("C");
stack.add("D");
stack.add("E");
// print stack
System.out.println("Original stack: "
+ stack);
// getting the subList
// using subList() method
List<String> stack2 = stack.subList(2, 4);
// print the subList
System.out.println("SubStack of stack: "
+ stack2);
}
catch (Exception e) {
System.out.println(e);
}
}
}
輸出:
Original stack: [A, B, C, D, E] SubStack of stack: [C, D]
示例2:對於IndexOutOfBoundsException
// Java program to demonstrate
// subList() method
// for IndexOutOfBoundsException
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
// Creating object of Stack<Integer>
Stack<String>
stack = new Stack<String>();
// Populating stack1
stack.add("A");
stack.add("B");
stack.add("C");
stack.add("D");
stack.add("E");
// print stack
System.out.println("Original stack: "
+ stack);
// getting the subList
// using subList() method
System.out.println("\nEnd index value is out of range");
List<String> stack2 = stack.subList(2, 7);
// print the subList
System.out.println("SubStack of stack: "
+ stack2);
}
catch (Exception e) {
System.out.println(e);
}
}
}
輸出:
Original stack: [A, B, C, D, E] End index value is out of range java.lang.IndexOutOfBoundsException: toIndex = 7
示例3:對於IllegalArgumentException
// Java program to demonstrate
// subList() method
// for IllegalArgumentException
import java.util.*;
public class GFG1 {
public static void main(String[] argv) throws Exception
{
try {
// Creating object of Stack<Integer>
Stack<String>
stack = new Stack<String>();
// Populating stack1
stack.add("A");
stack.add("B");
stack.add("C");
stack.add("D");
stack.add("E");
// print stack
System.out.println("Original stack: "
+ stack);
// getting the subList
// using subList() method
System.out.println("\nEndpoint indices "
+ "are out of order"
+ " (fromIndex > toIndex)");
List<String> stack2 = stack.subList(7, 2);
// print the subList
System.out.println("SubStack of stack: "
+ stack2);
}
catch (Exception e) {
System.out.println(e);
}
}
}
輸出:
Original stack: [A, B, C, D, E] Endpoint indices are out of order (fromIndex > toIndex) java.lang.IllegalArgumentException: fromIndex(7) > toIndex(2)
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注:本文由純淨天空篩選整理自Code_r大神的英文原創作品 Stack subList() method in Java with Example。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。