Java Stack contains()用法及代碼示例

java.util.Stack.contains()方法用於檢查堆棧中是否存在特定元素。因此，本質上，它用於檢查Stack是否包含任何特定元素。

用法:

Stack.contains(Object element)

參數：此方法采用了Stack類型的必需參數element 。如果堆棧中不存在此元素，則需要對其進行測試。

返回值：如果元素存在於堆棧中，則此方法返回True，否則返回False。

以下示例程序旨在說明Java.util.Stack.contains()方法：

示例1:

// Java code to illustrate contains() 
import java.util.*; 
  
public class StackDemo { 
    public static void main(String args[]) 
    { 
        // Creating an empty Stack 
        Stack<String> stack = new Stack<String>(); 
  
        // Use add() method to add elements into the Stack 
        stack.add("Welcome"); 
        stack.add("To"); 
        stack.add("Geeks"); 
        stack.add("4"); 
        stack.add("Geeks"); 
  
        // Displaying the Stack 
        System.out.println("Stack: " + stack); 
  
        // Check for "Geeks" in the Stack 
        System.out.println("Does the Stack contains 'Geeks'? "
                           + stack.contains("Geeks")); 
  
        // Check for "4" in the Stack 
        System.out.println("Does the Stack contains '4'? "
                           + stack.contains("4")); 
  
        // Check if the Queue contains "No" 
        System.out.println("Does the Stack contains 'No'? "
                           + stack.contains("No")); 
    } 
}

輸出：

Stack: [Welcome, To, Geeks, 4, Geeks]
Does the Stack contains 'Geeks'? true
Does the Stack contains '4'? true
Does the Stack contains 'No'? false

示例2:

// Java code to illustrate contains() 
import java.util.*; 
  
public class StackDemo { 
    public static void main(String args[]) 
    { 
        // Creating an empty Stack 
        Stack<Integer> stack = new Stack<Integer>(); 
  
        // Use add() method to add elements into the Stack 
        stack.add(10); 
        stack.add(15); 
        stack.add(30); 
        stack.add(20); 
        stack.add(5); 
  
        // Displaying the Stack 
        System.out.println("Stack: " + stack); 
  
        // Check for "Geeks" in the Stack 
        System.out.println("Does the Stack contains 'Geeks'? "
                           + stack.contains("Geeks")); 
  
        // Check for "4" in the Stack 
        System.out.println("Does the Stack contains '4'? "
                           + stack.contains("4")); 
  
        // Check if the Stack contains "No" 
        System.out.println("Does the Stack contains 'No'? "
                           + stack.contains("No")); 
    } 
}

輸出：

Stack: [10, 15, 30, 20, 5]
Does the Stack contains 'Geeks'? false
Does the Stack contains '4'? false
Does the Stack contains 'No'? false

相關用法

注：本文由純淨天空篩選整理自Code_r大神的英文原創作品 Stack contains() method in Java with Example。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。