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Java Stack contains()用法及代码示例


java.util.Stack.contains()方法用于检查堆栈中是否存在特定元素。因此,本质上,它用于检查Stack是否包含任何特定元素。

用法:

Stack.contains(Object element)

参数:此方法采用了Stack类型的必需参数element 。如果堆栈中不存在此元素,则需要对其进行测试。


返回值:如果元素存在于堆栈中,则此方法返回True,否则返回False。

以下示例程序旨在说明Java.util.Stack.contains()方法:

示例1:

// Java code to illustrate contains() 
import java.util.*; 
  
public class StackDemo { 
    public static void main(String args[]) 
    { 
        // Creating an empty Stack 
        Stack<String> stack = new Stack<String>(); 
  
        // Use add() method to add elements into the Stack 
        stack.add("Welcome"); 
        stack.add("To"); 
        stack.add("Geeks"); 
        stack.add("4"); 
        stack.add("Geeks"); 
  
        // Displaying the Stack 
        System.out.println("Stack: " + stack); 
  
        // Check for "Geeks" in the Stack 
        System.out.println("Does the Stack contains 'Geeks'? "
                           + stack.contains("Geeks")); 
  
        // Check for "4" in the Stack 
        System.out.println("Does the Stack contains '4'? "
                           + stack.contains("4")); 
  
        // Check if the Queue contains "No" 
        System.out.println("Does the Stack contains 'No'? "
                           + stack.contains("No")); 
    } 
}
输出:
Stack: [Welcome, To, Geeks, 4, Geeks]
Does the Stack contains 'Geeks'? true
Does the Stack contains '4'? true
Does the Stack contains 'No'? false

示例2:

// Java code to illustrate contains() 
import java.util.*; 
  
public class StackDemo { 
    public static void main(String args[]) 
    { 
        // Creating an empty Stack 
        Stack<Integer> stack = new Stack<Integer>(); 
  
        // Use add() method to add elements into the Stack 
        stack.add(10); 
        stack.add(15); 
        stack.add(30); 
        stack.add(20); 
        stack.add(5); 
  
        // Displaying the Stack 
        System.out.println("Stack: " + stack); 
  
        // Check for "Geeks" in the Stack 
        System.out.println("Does the Stack contains 'Geeks'? "
                           + stack.contains("Geeks")); 
  
        // Check for "4" in the Stack 
        System.out.println("Does the Stack contains '4'? "
                           + stack.contains("4")); 
  
        // Check if the Stack contains "No" 
        System.out.println("Does the Stack contains 'No'? "
                           + stack.contains("No")); 
    } 
}
输出:
Stack: [10, 15, 30, 20, 5]
Does the Stack contains 'Geeks'? false
Does the Stack contains '4'? false
Does the Stack contains 'No'? false


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注:本文由纯净天空筛选整理自Code_r大神的英文原创作品 Stack contains() method in Java with Example。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。