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Java Scanner findInLine()用法及代码示例


findInLine(Pattern pattern)

java.util.Scanner类的findInLine(Pattern pattern)方法尝试忽略分隔符来查找指定模式的下一个匹配项。如果在下一个行分隔符之前找到该模式，则扫描程序将前进经过匹配的输入并返回与该模式匹配的字符串。如果直到下一个行分隔符的输入中都未检测到这种模式，则返回null，并且扫描仪的位置不变。

用法:

public String findInLine(Pattern pattern)

参数：该函数接受强制参数“图案图案”，即要扫描的图案。


返回值：该函数返回扫描仪的定界图案。

异常：如果关闭此扫描器，则此函数将引发IllegalStateException。

以下示例程序旨在说明上述函数：

示例1:

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
  
            // close the scanner 
            scanner.close(); 
        } 
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}
输出： 
Target String:
Geeksforgeeks has Scanner Class Methods

Any 5 letter plus for : Geeksfor

示例2:演示IllegalStateException

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // close the scanner 
            scanner.close(); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
  
            // print the next line of the string 
            System.out.println("" + scanner.nextLine()); 
        } 
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown: " + e); 
        } 
    } 
}
输出： 
Target String:
Geeksforgeeks has Scanner Class Methods
Exception thrown:
 java.lang.IllegalStateException:
 Scanner closed

findInLine(String pattern)

java.util.Scanner类的findInLine(String pattern)方法尝试查找由指定的字符串模式构造的模式的下一次出现，而忽略了分隔符。

用法:

public String findInLine(String pattern)

参数：该函数接受扫描的强制性参数字符串模式。


返回值：该函数返回扫描仪的定界图案。

异常：如果关闭此扫描器，则此函数将引发IllegalStateException。

以下示例程序旨在说明上述函数：

示例1:

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
  
            // close the scanner 
            scanner.close(); 
        } 
  
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}
输出： 
Target String:
Geeksforgeeks has Scanner Class Methods

Any 5 letter plus for : Geeksfor

示例2:演示IllegalStateException

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // close the scanner 
            scanner.close(); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
        } 
  
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}
输出： 
Target String:
Geeksforgeeks has Scanner Class Methods
Exception thrown :
 java.lang.IllegalStateException:
 Scanner closed

参考： https://docs.oracle.com/javase/7/docs/api/java/util/Scanner.html#findInLine(java.util.regex.Pattern)

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注：本文由纯净天空筛选整理自gopaldave大神的英文原创作品 Scanner findInLine() method in Java with Examples。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。