Java Scanner findInLine()用法及代碼示例

findInLine(Pattern pattern)

java.util.Scanner類的findInLine(Pattern pattern)方法嘗試忽略分隔符來查找指定模式的下一個匹配項。如果在下一個行分隔符之前找到該模式，則掃描程序將前進經過匹配的輸入並返回與該模式匹配的字符串。如果直到下一個行分隔符的輸入中都未檢測到這種模式，則返回null，並且掃描儀的位置不變。

用法:

public String findInLine(Pattern pattern)

參數：該函數接受強製參數“圖案圖案”，即要掃描的圖案。

返回值：該函數返回掃描儀的定界圖案。

異常：如果關閉此掃描器，則此函數將引發IllegalStateException。

以下示例程序旨在說明上述函數：

示例1:

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
  
            // close the scanner 
            scanner.close(); 
        } 
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}

輸出：

Target String:
Geeksforgeeks has Scanner Class Methods

Any 5 letter plus for : Geeksfor

示例2:演示IllegalStateException

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // close the scanner 
            scanner.close(); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
  
            // print the next line of the string 
            System.out.println("" + scanner.nextLine()); 
        } 
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown: " + e); 
        } 
    } 
}

輸出：

Target String:
Geeksforgeeks has Scanner Class Methods
Exception thrown:
 java.lang.IllegalStateException:
 Scanner closed

findInLine(String pattern)

java.util.Scanner類的findInLine(String pattern)方法嘗試查找由指定的字符串模式構造的模式的下一次出現，而忽略了分隔符。

用法:

public String findInLine(String pattern)

參數：該函數接受掃描的強製性參數字符串模式。

返回值：該函數返回掃描儀的定界圖案。

異常：如果關閉此掃描器，則此函數將引發IllegalStateException。

以下示例程序旨在說明上述函數：

示例1:

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
  
            // close the scanner 
            scanner.close(); 
        } 
  
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}

輸出：

Target String:
Geeksforgeeks has Scanner Class Methods

Any 5 letter plus for : Geeksfor

示例2:演示IllegalStateException

// Java program to illustrate the 
// findInLine() method of Scanner class in Java 
  
import java.util.*; 
import java.util.regex.Pattern; 
  
public class GFG1 { 
    public static void main(String[] argv) 
        throws Exception 
    { 
  
        try { 
  
            // Get the string to be searched 
            String s = "Geeksforgeeks has Scanner Class Methods"; 
  
            // Print the string 
            System.out.println("Target String:\n" + s); 
  
            // create a new scanner 
            // with the specified String Object 
            Scanner scanner = new Scanner(s); 
  
            // close the scanner 
            scanner.close(); 
  
            // finds a pattern of any 5 letter plus "for" 
            System.out.println("\nAny 5 letter plus for : "
                               + scanner.findInLine( 
                                     Pattern.compile(".....for"))); 
        } 
  
        catch (IllegalStateException e) { 
            System.out.println("Exception thrown : " + e); 
        } 
    } 
}

輸出：

Target String:
Geeksforgeeks has Scanner Class Methods
Exception thrown :
 java.lang.IllegalStateException:
 Scanner closed

參考： https://docs.oracle.com/javase/7/docs/api/java/util/Scanner.html#findInLine(java.util.regex.Pattern)

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