assertStringNotContainsString()函数是PHPUnit中的内置函数,用于断言不包含子字符串的字符串。如果该字符串不包含子字符串,则该断言将返回true;否则,该断言将返回false;如果为true,则通过断言的测试用例,否则测试用例将失败。
用法:
assertStringNotContainsString(string $substring, string $string, string $message = ''])
参数:该函数接受三个参数,如上面的语法所示。参数说明如下:
- $substring:此参数表示字符串是给定字符串的子字符串。
- $string:此参数是一个字符串,assert函数将对其检查其是否包含子字符串。
- $message:此参数采用字符串值。当测试用例失败时,此字符串消息将显示为错误消息。
以下程序说明了PHPUnit中的assertStringNotContainsString()函数:
程序1:
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testNegativeTestcaseForAssertStringNotContainsString()
{
$testString = "geeksforgeek";
$substring = "geeks";
// Assert function to test whether 'geeks' is a
// substring of testString
$this->assertStringNotContainsString($substring, $testString,
"testString contains 'geeks' as substring") ;
}
}
?>
输出:
PHPUnit 8.2.5 by Sebastian Bergmann and contributors. F 1 / 1 (100%) Time:72 ms, Memory:10.00 MB There was 1 failure: 1) GeeksPhpunitTestCase::testNegativeTestcaseForAssertStringNotContainsString testString contains 'geeks' as substring Failed asserting that 'geeksforgeek' does not contain "geeks". /home/shivam/Documents/geeks/phpunit/abc.php:11 FAILURES! Tests:1, Assertions:1, Failures:1.
程序2:
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testPositiveTestcaseForAssertStringNotContainsString()
{
$testString = "geekforgeek";
$substring = "geeks";
// Assert function to test whether 'geeks' is a
// substring of testString
$this->assertStringNotContainsString($substring, $testString,
"testString contains 'geeks' as substring") ;
}
}
?>
输出:
PHPUnit 8.2.5 by Sebastian Bergmann and contributors. . 1 / 1 (100%) Time:67 ms, Memory:10.00 MB OK (1 test, 1 assertion)
注意:要使用phpunit运行测试用例,请遵循此处的步骤。另外,phpunit 7及更高版本支持assertStringNotContainsString()。
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注:本文由纯净天空筛选整理自Shivam.Pradhan大神的英文原创作品 PHPUnit | assertStringNotContainsString() Function。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。