assertArraySubset()函数是PHPUnit中的内置函数,用于声明具有子集的数组,如果该数组包含提供的子集,则该声明返回true;否则返回false;如果为true,则声明的测试用例通过否则测试用例失败。
用法:
assertArraySubset(array $subset, array $array[, bool $strict = false, string $message = ''])
参数:该函数接受四个参数,如以上语法所示。参数说明如下:
- $subset:此参数表示要包含在数组中的子集。
- $array:此参数是一个数组,assert函数将为其检查其是否包含子集。
- $strict:此参数是一个标志,用于比较数组中对象的身份。
- $message:此参数采用字符串值。当测试用例失败时,此字符串消息将显示为错误消息。
以下示例程序旨在说明assertArraySubset()函数:
程序1::
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testNegativeTestcaseForArraySubset()
{
$testArray = array("a"=>"value b", "b" =>" value b");
$subset = array("a"=> "value a");
// assert function to test whether 'subset' is a subset of array
$this->assertArraySubset($subset, $testArray, false, "testArray doesn't contains subset as subset") ;
}
}
?>
输出:
PHPUnit 6.5.5 by Sebastian Bergmann and contributors. F 1 / 1 (100%) Time:29 ms, Memory:4.00MB There was 1 failure: 1) GeeksPhpunitTestCase::testNegativeTestcaseForArraySubset testArray doesn't contains subset as subset Failed asserting that an array has the subset Array &0 ( 'a' => 'value a' ). --- Expected +++ Actual @@ @@ Array ( - [a] => value a + [a] => value b /home/shivam/Documents/geeks/phpunit/abc.php:11 FAILURES! Tests:1, Assertions:1, Failures:1.
程序2::
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testPositiveTestcaseForArraySubset()
{
$testArray = array("a"=>"value a", "b" =>" value b");
$subset = array("a"=> "value a");
// assert function to test whether 'subset' is a subset of array
$this->assertArraySubset($subset, $testArray, false, "testArray doesn't contains subset as subset") ;
}
}
?>
输出:
PHPUnit 6.5.5 by Sebastian Bergmann and contributors. . 1 / 1 (100%) Time:21 ms, Memory:4.00MB OK (1 test, 1 assertion)
注意:要使用phpunit运行测试用例,请遵循此处的步骤。
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注:本文由纯净天空筛选整理自Shivam.Pradhan大神的英文原创作品 PHPUnit | assertArraySubset() function。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。