assertIsResource()函数是PHPUnit中的内置函数,用于断言给定变量是否为Resource。如果给定变量为Resource,则此断言将返回true,否则返回false。如果为真,则通过断言的测试用例,否则测试用例失败。
用法:
assertIsResource($actual[, $message = ''])
参数:此函数接受上面和下面描述的两个参数:
- $variable:此参数可以是代表实际数据的任何类型的变量。
- $message:此参数采用字符串值。当测试用例失败时,此字符串消息将显示为错误消息。
以下示例说明了PHPUnit中的assertIsResource()函数:
范例1:
PHP
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testNegativeTestcaseForassertIsResource()
{
$variable = 555;
// Assert function to test whether assert
// variable is resource or not
$this->assertIsResource(
$variable,
"assert variable is resource or not"
);
}
}
?>
输出:
PHPUnit 8.5.8 by Sebastian Bergmann and contributors. F 1 / 1 (100%) Time:89 ms, Memory:10.00 MB There was 1 failure: 1) GeeksPhpunitTestCase::testNegativeTestcaseForassertIsResource assert variable is resource or not Failed asserting that 555 is of type "resource". /home/lovely/Documents/php/test.php:14 FAILURES! Tests:1, Assertions:1, Failures:1.
范例2:
PHP
<?php
use PHPUnit\Framework\TestCase;
class GeeksPhpunitTestCase extends TestCase
{
public function testPositiveTestcaseForassertIsResource()
{
$variable = fopen('http://www.google.com','r');
// Assert function to test whether assert
// variable is Iterable
$this->assertIsResource(
$variable,
"assert variable is Iterable or not"
);
fclose($variable);
}
}
?>
输出:
PHPUnit 8.5.8 by Sebastian Bergmann and contributors. . 1 / 1 (100%) Time:613 ms, Memory:10.00 MB OK (1 test, 1 assertion)
参考: https://phpunit.readthedocs.io/en/9.2/assertions.html#assertisresource
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注:本文由纯净天空筛选整理自shubham_singh大神的英文原创作品 PHPUnit assertIsResource() Function。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。