PHP PHPUnit assertFinite()用法及代码示例

assertFinite()函数是PHPUnit中的内置函数，用于断言实际获得的值是否不是INF。如果实际值不是INF，则此断言将返回true，否则返回false。如果为真，则通过断言的测试用例，否则测试用例失败。

用法:

assertFinite(mixed $variable[, string $message = ''])

参数：此函数接受上述和以下描述的两个参数：

• $actualvariable:此参数可以是代表实际值的任何类型的变量。
• $message:此参数采用字符串值。当测试用例失败时，此字符串消息将显示为错误消息。

以下示例说明了PHPUnit中的assertFinite()函数：

范例1：

<?php  
use PHPUnit\Framework\TestCase;  
    
class GeeksPhpunitTestCase extends TestCase  
{  
    public function testNegativeForassertFinite() 
          
    {     
     $actualvariable = INF; 
        // Assert function to test whether actual  
        // variable Doesn't INF 
        $this->assertFinite( 
            $actualvariable,  
            "actual variable Doesn't INF"
        ); 
          
    } 
   
 }  
?> 

输出：

PHPUnit 8.5.8 by Sebastian Bergmann and contributors.

F                                                  1 / 1 (100%)

Time:87 ms, Memory:10.00 MB

There was 1 failure:

1) GeeksPhpunitTestCase::testPositiveForassertFinite
actual variable Doesn't INF
Failed asserting that INF is finite.

/home/lovely/Documents/php/test.php:15

FAILURES!
Tests:1, Assertions:1, Failures:1.

范例2：

<?php  
use PHPUnit\Framework\TestCase;  
    
class GeeksPhpunitTestCase extends TestCase  
{  
    public function testPositiveForassertFinite() 
          
    {     
     $actualvariable = 108; 
        // Assert function to test whether actual  
        // variable Doesn't INF 
        $this->assertFinite( 
            $actualvariable,  
            "actual variable Doesn't INF"
        ); 
          
    } 
   
 }  
?> 

输出：

PHPUnit 8.5.8 by Sebastian Bergmann and contributors.

.                                                 1 / 1 (100%)

Time:90 ms, Memory:10.00 MB

OK (1 test, 1 assertion)