Guava LongMath类的方法pow(long b,int k)将b返回到第k次幂。即使结果溢出,也将等于BigInteger.valueOf(b).pow(k).longValue()。此实现在O(log k)时间中运行。
用法:
public static long pow(long b, int k)
参数:该方法接受两个参数b和k。参数b称为基数,它升为k-th的幂。
返回值:此方法返回b的k-th幂。
异常:如果k为负,则此方法引发IllegalArgumentException。
范例1:
// Java code to show implementation of
// pow(long b, int k) method of Guava's
// LongMath Class
import java.math.RoundingMode;
import com.google.common.math.LongMath;
class GFG {
// Driver code
public static void main(String args[])
{
long b1 = 4;
int k1 = 5;
long ans1 = LongMath.pow(b1, k1);
System.out.println(b1 + " to the " + k1
+ "th power is:"
+ ans1);
long b2 = 12;
int k2 = 3;
long ans2 = LongMath.pow(b2, k2);
System.out.println(b2 + " to the " + k2
+ "rd power is:"
+ ans2);
}
}
输出:
4 to the 5th power is:1024 12 to the 3rd power is:1728
范例2:
// Java code to show implementation of
// pow(long b, int k) method of Guava's
// LongMath class
import java.math.RoundingMode;
import com.google.common.math.LongMath;
class GFG {
static long findPow(long b, int k)
{
try {
// Using pow(long b, int k)
// method of Guava's LongMath class
// This should throw "IllegalArgumentException"
// as k < 0
long ans = LongMath.pow(b, k);
// Return the answer
return ans;
}
catch (Exception e) {
System.out.println(e);
return -1;
}
}
// Driver code
public static void main(String args[])
{
long b = 4;
int k = -5;
try {
// Using pow(long b, int k)
// method of Guava's LongMath class
// This should throw "IllegalArgumentException"
// as k < 0
LongMath.pow(b, k);
}
catch (Exception e) {
System.out.println(e);
}
}
}
输出:
java.lang.IllegalArgumentException:exponent (-5) must be >= 0
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注:本文由纯净天空筛选整理自Sahil_Bansall大神的英文原创作品 Java Guava | pow(long b, int k) of LongMath Class with Examples。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。