Guava LongMath类的二项式(int n,int k)方法接受两个参数n和k并计算二项式系数的值。如果计算的值超出long的最大值,则该方法返回Long.MAX_VALUE,即long的最大值。
用法:
public static long binomial(int n, int k)
参数:此方法接受两个参数n和k并计算二项式系数的值。
返回值:该方法返回n和k的二项式系数。
异常:如果n为负数,或k为负数或k大于n,则方法binomial(int n,int k)引发IllegalArgumentException。
下面的示例说明LongMath类的binomial()方法:
范例1:
// Java code to show implementation of
// binomial(int n, int k) method of Guava's
// LongMath class
import java.math.RoundingMode;
import com.google.common.math.LongMath;
class GFG {
// Driver code
public static void main(String args[])
{
int n = 4;
int k = 3;
// Using binomial(int n, int k) method of
// Guava's LongMath class
long ans = LongMath.binomial(n, k);
System.out.println("Binomial Coefficient of "
+ n + " and " + k
+ " is:" + ans);
int n1 = 20;
int k1 = 4;
// Using binomial(int n, int k) method of
// Guava's LongMath class
long ans1 = LongMath.binomial(n1, k1);
System.out.println("Binomial Coefficient of "
+ n1 + " and " + k1
+ " is:" + ans1);
}
}
输出:
Binomial Coefficient of 4 and 3 is:4 Binomial Coefficient of 20 and 4 is:4845
范例2:
// Java code to show implementation of
// binomial(int n, int k) method of Guava's
// LongMath class
import java.math.RoundingMode;
import com.google.common.math.LongMath;
class GFG {
static long findBinomial(int n, int k)
{
try {
// Using binomial(int n, int k)
// method of Guava's LongMath class
// This should throw "IllegalArgumentException"
// as k < 0
long ans = LongMath.binomial(n, k);
// Return the answer
return ans;
}
catch (Exception e) {
System.out.println(e);
return -1;
}
}
// Driver code
public static void main(String args[])
{
int n = 5;
int k = 7;
try {
// Function calling
findBinomial(n, k);
}
catch (Exception e) {
System.out.println(e);
}
}
}
输出:
java.lang.IllegalArgumentException:k (7) > n (5)
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注:本文由纯净天空筛选整理自Sahil_Bansall大神的英文原创作品 Java Guava | binomial(int n, int k) of LongMath Class with Examples。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。