Java BigInteger sqrt()用法及代码示例

java.math.BigInteger.byteValueExact()是Java SE 9和JDK 9中添加的一个内置函数，该函数返回应用了sqrt()方法的BigInteger平方根的BigInteger值。它与floor(sqrt(n))相同，其中n是一个数字。如果不能将实平方根表示为整数值，则此平方根小于实平方根。

用法:

public BigInteger sqrt()

参数：该方法不带任何参数。
返回值：方法返回此BigInteger的整数平方根。
异常：如果BigInteger为负，则该方法将引发ArithmeticException。

例：

Input: 234876543456
Output: 484640
Explanation: 122 is given as input which is the bigInteger.
The square root of 122 is 11.04536
whose BigInteger equivalent is 11 and using sqrt()
method of BigInteger class we can get
Square root of any BigInteger.

Input: 122
Output: 11

以下示例程序旨在说明BigInteger类的sqrt()方法：

示例1:显示了sqrt()方法在获得31739平方根中的应用。

// Please run this program in JDK 9 or JDK 10 
// Java program to demonstrate sqrt() method 
import java.math.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Creating a BigInteger object 
        BigInteger big, squareRoot; 
  
        big = new BigInteger("31739"); 
  
        // calculate square root o bigInteger 
        // using sqrt() method 
        squareRoot = big.sqrt(); 
  
        // print result 
        System.out.println("Square root value of BigInteger " + big 
                           + " is " + squareRoot); 
    } 
}

输出：

Square root value of BigInteger 31739 is 178

示例2:显示由sqrt()方法引发的异常。

//Please run this program in JDK 9 or JDK 10 
// Java program to demonstrate sqrt() method 
//and exception thrown by it 
import java.math.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Creating a BigInteger object 
        BigInteger big,squareRoot=null; 
  
        big = new BigInteger("-2345"); 
  
        //calculate square root o bigInteger 
        //using sqrt() method 
        try { 
            squareRoot = big.sqrt(); 
        } catch (Exception e) { 
            e.printStackTrace(); 
        } 
  
        // print result 
        System.out.println("Square root value of BigInteger " + big 
                +" is "+squareRoot); 
    } 
}

输出：

java.lang.ArithmeticException: Negative BigInteger
    at java.base/java.math.BigInteger.sqrt(Unknown Source)
    at GFG.main(GFG.java:19)
Square root value of BigInteger -2345 is null

参考： https://docs.oracle.com/javase/9/docs/api/java/math/BigInteger.html#sqrt–

相关用法

注：本文由纯净天空筛选整理自AmanSingh2210大神的英文原创作品 BigInteger sqrt() Method in Java。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。