Java BigInteger mod()用法及代码示例

java.math.BigInteger.mod(BigInteger big)方法返回一个值等于(此BigInteger mod函数big(BigInteger作为参数传递))的BigInteger。换句话说，我们可以说该方法执行后返回值(this ％big)步骤.mod操作将此BigInteger除以作为参数传递的另一个BigInteger之后找到余数。

java.math.BigInteger.mod(BigInteger big)和java.math.BigInteger.remainder(BigInteger val)都可以找到余数，但mod操作始终返回非负的BigInteger。

用法:

public BigInteger mod(BigInteger big)

参数：该函数接受单个必填参数big，该参数指定了我们要用来划分此bigInteger对象的BigInteger对象。

返回值：该方法返回的BigInteger等于此BigInteger mod big(作为参数传递的BigInteger)。

异常：当big≤0时，该方法引发ArithmeticException

例子：

Input: BigInteger1=321456, BigInteger2=31711
Output: 4346
Explanation: BigInteger1.mod(BigInteger2)=4346. The divide operation between 
321456 and 31711 returns 4346 as remainder.

Input: BigInteger1=59185482345, BigInteger2=59185482345
Output: 0
Explanation: BigInteger1.mod(BigInteger2)=0. The divide operation between 
59185482345 and 59185482345 returns 0 as remainder.

下面的程序说明BigInteger类的mod()方法：

示例1:

// Java program to demonstrate mod() method of BigInteger 
  
import java.math.BigInteger; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Creating 2 BigInteger objects 
        BigInteger b1, b2; 
  
        b1 = new BigInteger("321456"); 
        b2 = new BigInteger("31711"); 
  
        // apply mod() method 
        BigInteger result = b1.mod(b2); 
  
        // print result 
        System.out.println("Result of mod  
                 operation between " + b1 
                 + " and " + b2 + 
                 " equal to " + result); 
    } 
}

输出：

Result of mod operation between 321456 and 31711 equal to 4346

示例2:当两者的价值相等时。

// Java program to demonstrate mod() method of BigInteger 
  
import java.math.BigInteger; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Creating 2 BigInteger objects 
        BigInteger b1, b2; 
  
        b1 = new BigInteger("3515219485"); 
        b2 = new BigInteger("3515219485"); 
  
        // apply mod() method 
        BigInteger result = b1.mod(b2); 
  
        // print result 
        System.out.println("Result of mod  
                 operation between " + b1 
                 + " and " + b2 + 
                 " equal to " + result); 
    } 
}

输出：

Result of mod operation between 3515219485 and 3515219485 equal to 0

示例3:当BigInteger作为参数传递时，程序显示异常小于零。

// Java program to demonstrate mod() method of BigInteger 
  
import java.math.BigInteger; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Creating 2 BigInteger objects 
        BigInteger b1, b2; 
  
        b1 = new BigInteger("3515219485"); 
        b2 = new BigInteger("-1711"); 
  
        // apply mod() method 
        BigInteger result = b1.mod(b2); 
  
        // print result 
        System.out.println("Result of mod  
                 operation between " + b1 
                 + " and " + b2 + 
                 " equal to " + result); 
    } 
}

输出：

Exception in thread "main" java.lang.ArithmeticException: BigInteger: modulus not positive
    at java.math.BigInteger.mod(BigInteger.java:2458)
    at GFG.main(GFG.java:17)

参考： https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#mod(java.math.BigInteger)

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注：本文由纯净天空筛选整理自AmanSingh2210大神的英文原创作品 BigInteger mod() Method in Java。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。