Java BigInteger or()用法及代码示例

先决条件：BigInteger基础

java.math.BigInteger.or(BigInteger val)方法用于对两个BigInteger进行按位或运算。一个BigInteger传入参数，另一个传入该函数。如果与该函数一起使用的BigIntegers之一为负，则此方法返回负数。 BigInteger的OR()方法对作为参数传递的当前bigInteger和bigInteger应用按位或运算。

用法:

public BigInteger or(BigInteger val)

参数：该方法接受BigInteger类型的一个参数val，表示与此BigInteger进行或运算的值。

返回值：该方法返回带有bigInteger val的当前bigInteger的bitwise-OR。

例：

Input: value1 = 2300 , value2 = 3400
Output: 3580
Explanation:
Binary of 2300 = 100011111100
Binary of 3400 = 110101001000
OR of 100011111100 and 110101001000 = 110111111100
Decimal of 110111111100 = 3580.

Input: value1 = 54298 , value2 = 64257
Output: 65307

以下示例程序旨在说明BigInteger类的or()方法：

/* 
*Program Demonstrate or() method of BigInteger  
*/
import java.math.*; 
  
public class GFG { 
  
    public static void main(String[] args) 
    { 
  
        // Creates 2 BigInteger objects 
        BigInteger biginteger = new BigInteger("2300"); 
        BigInteger val = new BigInteger("3400"); 
  
        // Call or() method to find (biginteger | val) 
        BigInteger biggerInteger = biginteger.or(val); 
  
        String result = "Result of OR operation between " + biginteger + " and "
                        + val + " is " + biggerInteger; 
  
        // Print result 
        System.out.println(result); 
    } 
}

Result of OR operation between 2300 and 3400 is 3580

参考： https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#or(java.math.BigInteger)