Java AbstractSequentialList set(int, Object)用法及代码示例

Java AbstractSequentialList的set()方法用于将使用AbstractSequentialList类创建的列表中的任何特定元素替换为另一个元素。这可以通过在set()方法的参数中指定要替换的元素的位置和新元素来完成。

用法:

public E set(int index, Object element)

参数：该函数接受两个参数，如上面的语法所示，如下所述。

index：这是整数类型，是指要从列表中替换的元素的位置。
element：这是将替换现有元素的新元素，并且与列表具有相同的对象类型。

返回值：该方法从列表中返回被新值替换的先前值。

异常：此方法引发以下异常：

UnsupportedOperationException：如果此列表不支持设置操作
ClassCastException：如果指定元素的类阻止将其添加到此列表中
NullPointerException ：如果指定的元素为null，并且此列表不允许为null
IllegalArgumentException：如果指定元素的某些属性阻止将其添加到此列表
IndexOutOfBoundsException：如果索引超出范围(索引= size())

以下示例程序旨在说明Java.util.AbstractSequentialList.set()方法：

范例1：

// Java code to illustrate set() 
  
import java.io.*; 
import java.util.*; 
  
public class AbstractSequentialListDemo { 
    public static void main(String args[]) 
    { 
        // Creating an empty AbstractSequentialList 
        AbstractSequentialList<String> list 
            = new LinkedList<String>(); 
  
        // Use add() method to add elements in the list 
        list.add("Geeks"); 
        list.add("for"); 
        list.add("Geeks"); 
        list.add("10"); 
        list.add("20"); 
  
        // Displaying the linkedlist 
        System.out.println("AbstractSequentialList:"
                           + list); 
  
        // Using set() method to replace Geeks with GFG 
        System.out.println("The Object that is replaced is:"
                           + list.set(2, "GFG")); 
  
        // Using set() method to replace 20 with 50 
        System.out.println("The Object that is replaced is:"
                           + list.set(4, "50")); 
  
        // Displaying the modified linkedlist 
        System.out.println("The new AbstractSequentialList is:"
                           + list); 
    } 
}

输出：

AbstractSequentialList:[Geeks, for, Geeks, 10, 20]
The Object that is replaced is:Geeks
The Object that is replaced is:20
The new AbstractSequentialList is:[Geeks, for, GFG, 10, 50]

范例2：演示IndexOutOfBoundException

// Java code to illustrate set() 
  
import java.io.*; 
import java.util.*; 
  
public class AbstractSequentialListDemo { 
    public static void main(String args[]) 
    { 
        // Creating an empty AbstractSequentialList 
        AbstractSequentialList<String> list 
            = new LinkedList<String>(); 
  
        // Use add() method to add elements in the list 
        list.add("Geeks"); 
        list.add("for"); 
        list.add("Geeks"); 
        list.add("10"); 
        list.add("20"); 
  
        // Displaying the linkedlist 
        System.out.println("AbstractSequentialList:"
                           + list); 
  
        // Using set() method to replace 10th with GFG 
        // and the 10th element does not exist 
        System.out.println("Trying to replace 10th "
                           + "element with GFG"); 
  
        try { 
            list.set(10, "GFG"); 
        } 
        catch (Exception e) { 
            System.out.println(e); 
        } 
    } 
}

输出：

AbstractSequentialList:[Geeks, for, Geeks, 10, 20]
Trying to replace 10th element with GFG
java.lang.IndexOutOfBoundsException:Index:10, Size:5

相关用法

注：本文由纯净天空筛选整理自Code_r大神的英文原创作品 AbstractSequentialList set(int, Object) method in Java with Example。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。