Java AbstractSequentialList contains()用法及代码示例

Java AbstractSequentialList的contains()方法用于检查Collection中是否存在元素。它使用元素作为参数，如果元素存在于集合中，则返回True。

用法:

public boolean contains(Object element)

参数：参数element 的类型为Collection。此参数表示需要在集合中检查其出现的元素。

返回值：该方法返回一个布尔值。如果元素存在于Collection中，则返回True，否则返回False。

以下示例程序旨在说明AbstractSequentialList.contains()方法：

程序1:

// Java code to illustrate 
// AbstractSequentialList.contains() 
  
import java.util.*; 
  
public class GFG { 
    public static void main(String args[]) 
    { 
  
        // Creating an empty Collection 
        AbstractSequentialList<String> 
            abs = new LinkedList<String>(); 
  
        // Use add() method to add 
        // elements in the collection 
        abs.add("Geeks"); 
        abs.add("for"); 
        abs.add("Geeks"); 
        abs.add("10"); 
        abs.add("20"); 
  
        // Displaying the collection 
        System.out.println("AbstractSequentialList:"
                           + abs); 
  
        // Check if the collection contains "Hello" 
        System.out.println("\nDoes the Collection"
                           + " contains 'Hello':"
                           + abs.contains("Hello")); 
  
        // Check if the Collection contains "20" 
        System.out.println("Does the collection"
                           + " contains '20':"
                           + abs.contains("20")); 
  
        // Check if the Collection contains "Geeks" 
        System.out.println("Does the Collection"
                           + " contains 'Geeks':"
                           + abs.contains("Geeks")); 
    } 
}

输出：

AbstractSequentialList:[Geeks, for, Geeks, 10, 20]

Does the Collection contains 'Hello':false
Does the collection contains '20':true
Does the Collection contains 'Geeks':true

程序2:

// Java code to illustrate 
// AbstractSequentialList.contains() 
  
import java.util.*; 
  
public class GFG { 
    public static void main(String args[]) 
    { 
  
        // Creating an empty Collection 
        AbstractSequentialList<Integer> 
            abs = new LinkedList<Integer>(); 
  
        // Use add() method to add 
        // elements in the collection 
        abs.add(10); 
        abs.add(20); 
        abs.add(30); 
        abs.add(40); 
        abs.add(50); 
  
        // Displaying the collection 
        System.out.println("AbstractSequentialList:"
                           + abs); 
  
        // Check if the collection contains 10 
        System.out.println("\nDoes the Collection "
                           + "contains '10':"
                           + abs.contains(10)); 
  
        // Check if the collection contains 50 
        System.out.println("\nDoes the Collection"
                           + " contains '50':"
                           + abs.contains(50)); 
  
        // Check if the Collection contains 100 
        System.out.println("Does the collection"
                           + " contains '100':"
                           + abs.contains(100)); 
    } 
}

输出：

AbstractSequentialList:[10, 20, 30, 40, 50]

Does the Collection contains '10':true

Does the Collection contains '50':true
Does the collection contains '100':false

相关用法

注：本文由纯净天空筛选整理自Code_r大神的英文原创作品 AbstractSequentialList contains() method in Java with Example。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。