AbstractSequentialList的remove(int index)方法用于从特定位置或索引的抽象顺序列表中删除元素。
用法:
AbstractSequentialList.remove(int index)
参数:参数index是整数数据类型,它指定要从AbstractSequentialList中移除的元素的位置。
返回值:此方法返回刚刚从列表中删除的元素。
以下示例程序旨在说明AbstractSequentialList.remove(int index)方法:
程序1:
// Java code to illustrate remove() method
import java.util.*;
import java.util.AbstractSequentialList;
public class AbstractSequentialListDemo {
public static void main(String args[])
{
// Creating an empty AbstractSequentialList
AbstractSequentialList<String>
absqlist = new LinkedList<String>();
// Using add() method to add elements in the list
absqlist.add("Geeks");
absqlist.add("for");
absqlist.add("Geeks");
absqlist.add("10");
absqlist.add("20");
// Output the list
System.out.println("AbstractSequentialList:"
+ absqlist);
// Remove the head using remove()
absqlist.remove(3);
// Print the final list
System.out.println("Final List:"
+ absqlist);
}
}
输出:
AbstractSequentialList:[Geeks, for, Geeks, 10, 20] Final List:[Geeks, for, Geeks, 20]
程序2:
// Java code to illustrate remove()
// with position of element passed as parameter
import java.util.*;
import java.util.AbstractSequentialList;
public class AbstractSequentialListDemo {
public static void main(String args[])
{
// Creating an empty AbstractSequentialList
AbstractSequentialList<String>
absqlist = new LinkedList<String>();
// Use add() method to add elements in the list
absqlist.add("Geeks");
absqlist.add("for");
absqlist.add("Geeks");
absqlist.add("10");
absqlist.add("20");
// Output the list
System.out.println("AbstractSequentialList:"
+ absqlist);
// Remove the head using remove()
absqlist.remove(0);
// Print the final list
System.out.println("Final AbstractSequentialList:"
+ absqlist);
}
}
输出:
AbstractSequentialList:[Geeks, for, Geeks, 10, 20] Final AbstractSequentialList:[for, Geeks, 10, 20]
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注:本文由纯净天空筛选整理自Chinmoy Lenka大神的英文原创作品 AbstractSequentialList remove() method in Java with Examples。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。